在 Python 中跨多行和多列生成条件时间增量

Question

我正在处理天气数据，并试图计算与我的时间序列中每小时观测值相对应的日光分钟数。

London = pd.read_csv(root_dir + 'London.csv',
                     usecols=['date_time','London_sunrise','London_sunset'], 
                     parse_dates=['date_time'])

London.set_index(London['date_time'], inplace =True)

London['London_sunrise'] = pd.to_datetime(London['London_sunrise']).dt.strftime('%H:%M')
London['London_sunset'] = pd.to_datetime(London['London_sunset']).dt.strftime('%H:%M')
London['time'] = pd.to_datetime(London['date_time']).dt.strftime('%H:%M')

London['London_sun_mins'] = np.where(London['time']>=London['London_sunrise'], '60', '0')

London.head(6)

数据框：

date_time               time            London_sunrise  London_sunset   London_sun_mins     
2019-05-21 00:00:00     00:00           05:01           20:54           0
2019-05-21 01:00:00     01:00           05:01           20:54           0
2019-05-21 02:00:00     02:00           05:01           20:54           0
2019-05-21 03:00:00     03:00           05:01           20:54           0
2019-05-21 04:00:00     04:00           05:01           20:54           0
2019-05-21 05:00:00     05:00           05:01           20:54           0
2019-05-21 06:00:00     06:00           05:01           20:54           60

我已经尝试使用条件参数来生成每小时的日照分钟数，即）如果是完整的日照时间，则为 60，如果是夜晚，则为 0。

当我尝试使用 timedelta 来生成日出和时间之间的差异时，即 05:00 和 05:01，未返回预期的输出 (59)。

一个简单的： London['London_sun_mins'] = np.where(London['time']>=London['London_sunrise'], '60', '0')

但是，当我尝试扩展到：

London['London_sun_mins'] = np.where(London['time']>=London['London_sunrise'], London['time'] - London['London_sunrise'], '0')

返回以下错误： unsupported operand type(s) for -: 'str' and 'str'

此外，当扩展到包括日出和日落时：

London['sunlightmins'] = London[(London['London_sunrise'] >= London['date_time'] & London['London_sunset'] <= London['date_time'])]

London['London_sun_mins'] = np.where(np.logical_and(np.greater_equal(London['time'],London['London_sunrise']),np.less_equal(London['time'],London['London_sunset'])))

返回相同的错误。感谢您对达到预期输出的所有帮助！

Answer 1

我建议保留日期时间类型，以便您可以直接使用差异。实际上，您已将小时数转换为字符串，因此当您尝试减去它们时，它会给您此错误。 但是如果你有日期时间变量，你可以直接减去它们，如下所示：

# First I reproduce you dataset 
import pandas as pd
London = pd.DataFrame({"date_time": pd.date_range("2019-05-21", periods=7, freq = "H"),
                   "London_sunrise" : "05:01",
                   "London_sunset" : "20:54"})
# I extract the date from date_time
London["date"] = London["date_time"].dt.date
# Then I create a datetime variable for sunrise and sunset with the same date 
# as my date_time variable and the hour from London_sunset and London_sunrise
London["sunrise_dtime"] = London.apply(lambda r: str(r["date"]) + " " + \
                                    r["London_sunrise"] + ":00", 1)
London["sunset_dtime"] = London.apply(lambda r: str(r["date"]) + " " + \
                                    r["London_sunset"] + ":00", 1)
# I transform them to datetime
London['sunrise_dtime'] = pd.to_datetime(London['sunrise_dtime'])
London['sunset_dtime'] = pd.to_datetime(London['sunset_dtime'])

# Then I can substract the two datetimes:
London['London_sun_mins'] = np.where(London['date_time']>=London['sunrise_dtime'],
                                     London['date_time'] - London['sunrise_dtime'], 0)

结果如下：

           date_time London_sunrise  ...        sunset_dtime London_sun_mins
0 2019-05-21 00:00:00          05:01  ... 2019-05-21 20:54:00        00:00:00
1 2019-05-21 01:00:00          05:01  ... 2019-05-21 20:54:00        00:00:00
2 2019-05-21 02:00:00          05:01  ... 2019-05-21 20:54:00        00:00:00
3 2019-05-21 03:00:00          05:01  ... 2019-05-21 20:54:00        00:00:00
4 2019-05-21 04:00:00          05:01  ... 2019-05-21 20:54:00        00:00:00
5 2019-05-21 05:00:00          05:01  ... 2019-05-21 20:54:00        00:00:00
6 2019-05-21 06:00:00          05:01  ... 2019-05-21 20:54:00        00:59:00

希望对你有帮助