【发布时间】:2017-02-07 07:48:13
【问题描述】:
我正在尝试创建注册表单,但应用程序不断崩溃 我认为这可能是我的虚拟模拟器的 URL,我尝试了 10.0.2.2 和 10.0.3.2,我检查了虚拟框以查看要使用的地址,我得到了 192.168.79.2,但它们都不起作用。
这是我的 BackgroundTask.java 类
public class BackgroundTask extends
AsyncTask<String,Void,String> {
Context ctx;
BackgroundTask(Context ctx){
this.ctx=ctx;
}
@Override
protected void onPreExecute() {
super.onPreExecute();
}
@Override
protected String doInBackground(String... params) {
String method= params[0];
String reg_url="http://192.168.79.2/webapp/register.php";
// String login_url="http://10.0.2.2/webapp/login.php";
if(method.equals("register")){
String names=params[1];
String user_name=params[2];
String user_pass=params[3];
try {
URL url= new URL(reg_url);
HttpsURLConnection httpsURLConnection = (HttpsURLConnection)
url.openConnection();
httpsURLConnection.setRequestMethod("POST");
httpsURLConnection.setDoOutput(true);
OutputStream OS=httpsURLConnection.getOutputStream();
BufferedWriter bufferedWriter =new BufferedWriter(new
OutputStreamWriter(OS, "UTF-8"));
String data = URLEncoder.encode("user", "UTF-8")+"="+URLEncoder.encode(names, "UTF-8")+"&"+
URLEncoder.encode("user_name", "UTF-8")+"="+URLEncoder.encode(user_name, "UTF-8")+"&"+
URLEncoder.encode("user_pass", "UTF-8")+"="+URLEncoder.encode(user_pass, "UTF-8");
bufferedWriter.write(data);
bufferedWriter.flush();
OS.close();
InputStream IS = httpsURLConnection.getInputStream();
IS.close();
return "Registration success";
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
;
}
return null;
}
@Override
protected void onProgressUpdate(Void... values) {
super.onProgressUpdate(values);
}
@Override
protected void onPostExecute(String result) {
Toast.makeText(ctx,"result" ,Toast.LENGTH_LONG).show();
}
}
这是我的 Register.java 活动
public class Register extends Activity {
EditText ET_NAME, ET_USER_NAME, ET_USER_PASS;
String name, user_name, user_pass;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_register);
ET_NAME=(EditText) findViewById(R.id.name);
ET_USER_NAME=(EditText) findViewById(R.id.username);
ET_USER_PASS=(EditText) findViewById(R.id.pass);
}
public void userReg(View view){
name= ET_NAME.getText().toString();
user_name=ET_USER_NAME.getText().toString();
user_pass=ET_USER_PASS.getText().toString();
String method= "register";
BackgroundTask backgroundTask = new BackgroundTask(this);
backgroundTask.execute(method, name, user_name, user_pass);
finish();
}
}
这是我的 register.php 文件
<?php
require"init.php";
$names=$_POST["names"];
$user_name=$_POST["user_name"];
$user_pass=$_POST["user_pass"];
$sql_query="insert into info values('$names', '$user_name', '$user_pass');";
if(mysqli_query($con, $sql_query)){
//echo"<h3>Data insertion Success...</h3>";
}
else{
//echo"Data insertion error...".mysqli_error($con);
}
?>
【问题讨论】:
-
你的端口是什么?例如,我有 10.0.2.2:57714 然后 57714 是我的端口并在您的模拟器中检查应用程序
-
如何找到这个端口?以前从未尝试过!
-
试试这个:10.0.2.2:80/webapp/register.php 告诉我它对你有用吗?
-
10.0.3.2 工作我的导入出现问题
标签: php android mysql localhost wampserver