执行 curl 请求答案

【问题标题】：Doing a curl request执行 curl 请求
【发布时间】：2015-03-23 07:58:06
【问题描述】：

我正在尝试在网站上执行 curl 请求，但似乎无法正常工作。

这就是我所拥有的

<?php
 $mynumber = $_GET["mynumber"];
 echo $mynumber;
 $url = 'thewebsite/c/number='.$mynumber; // like this?
 $curl_header = array('X-Requested-With: XMLHttpRequest');
 $ch = curl_init($url);
 curl_setopt($ch, CURLOPT_HTTPHEADER, $curl_header);
 curl_setopt($ch, CURLOPT_POSTFIELDS, "number=$mynumber"); //??? --data     "number=12345678" ?
 curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
 curl_setopt($ch, CURLOPT_COOKIE, $cookie);
 curl_setopt($ch, CURLOPT_COOKIESESSION, TRUE);
 curl_setopt($ch, CURLOPT_VERBOSE, true);
 $result = curl_exec($ch);
 echo $result;
 curl_close($ch)
 ?>

这是 curl 请求：

"Content-Type: application/x-www-form-urlencoded; charset=UTF-8" -H "Accept: application/json, text/javascript, */*; q=0.01" -H "Referer: thewebsite" -H "X-Requested-With: XMLHttpRequest" -H "Connection: keep-alive" --data "number=12345678" --compressed  POST /thewebsite/c HTTP/1.1

我不知道如何传递 "--data "number=12345678"

【问题讨论】：

stackoverflow.com/questions/5224790/…
将print curl_error($ch) 放在cur_close 调用之前。你也错过了底部的;。可能是错字。
@Bjorn 是对的，只需添加所有标题。

标签： php curl

【解决方案1】：

您似乎正确地传递了--data 参数。但是您忘记设置Content-Type、Accept、Referer 和Connection 标头。您可以通过设置X-Requested-With 标头（在$curl_header 中）的方式添加它们：

<?php

$cookie = '';
$mynumber = $_GET['mynumber'];

$ch = curl_init('http://example.com/c/');

curl_setopt($ch, CURLOPT_HTTPHEADER, array(
    'X-Requested-With: XMLHttpRequest',
    'Content-Type: application/x-www-form-urlencoded; charset=UTF-8',
    'Accept: application/json, text/javascript, */*; q=0.01',
    'Referer: http://example.com/c/',
    'Connection: keep-alive'
));
curl_setopt($ch, CURLOPT_POSTFIELDS, "number=$mynumber");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_COOKIE, $cookie);
curl_setopt($ch, CURLOPT_COOKIESESSION, TRUE);
curl_setopt($ch, CURLOPT_VERBOSE, true);

$result = curl_exec($ch);
var_dump($result);

【讨论】：