preg_replace_callback - 做两次

Question

哟，我正在尝试使这个脚本工作，但它不起作用。我怎么做两次，preg_replace_callback 有两个不同的功能。谢谢！

 function prepend_proxy($matches) {
   $url = (substr($_GET['url'], 0, 7) == 'http://') ? $_GET['url'] : "http://{$_GET['url']}";
    $prepend = $matches[2] ? $matches[2] : $url;
    $prepend = 'proxy2.php?url='. $prepend .'/';

    return $matches[1] . $prepend . $matches[3];
}

function imgprepend_proxy($matches2) {
   $url = (substr($_GET['url'], 0, 7) == 'http://') ? $_GET['url'] : "http://{$_GET['url']}";
    $prepend2 = $matches2[2] ? $matches2[2] : $url;
    $prepend2 = $prepend2 .'/';

    return $matches2[1] . $prepend2 . $matches2[3];
}


$new_content = preg_replace_callback(
    '|(href=[\'"]?)(https?://)?([^\'"\s]+[\'"]?)|i',
    'prepend_proxy',
    '|(src=[\'"]?)(https?://)?([^\'"\s]+[\'"]?)|i',
    'imgprepend_proxy',
    $content
); 

Answer 1

$new_content = preg_replace_callback(
    '|(href=[\'"]?)(https?://)?([^\'"\s]+[\'"]?)|i',
    'prepend_proxy',
    preg_replace_callback(
        '|(src=[\'"]?)(https?://)?([^\'"\s]+[\'"]?)|i',
        'imgprepend_proxy',
        $content
    )
);