【发布时间】：2019-03-17 23:49:42
【问题描述】：
我在创建此登录系统时遇到问题。当有人登录时，我希望它创建一个表，如果还没有的话。然后将它们带到表单页面，然后插入数据。在最后一页插入之前，我一切正常。
Steam API 登录后
<?php
session_start();
require ('../../../mysql_connect/mysqli_connect_accounts.php');
require ('../steamauth/steamauth.php');
require ('../steamauth/userInfo.php');
$steamid=$_SESSION['steamid'];
$query = "SELECT * FROM `".$steamid."`";
$response = @mysqli_query($dbc, $query);
if($response){
header("Location: http://theskindealer.com/index.php");
} else {
$create = "CREATE TABLE `".$steamid."` (
steam64 VARCHAR(30),
fullname VARCHAR(60),
tradeurl VARCHAR(60),
email VARCHAR(50),
age INT(3),
tos INT(1),
access INT(1),
freeze INT(1),
balance DECIMAL(9,2),
newsletter INT(1),
emailVerified INT(1)
)";
if ($dbc->query($create) === TRUE) {
header("Location: http://theskindealer.com/scripts/createAccount.php");
} else {
header("Location: http://theskindealer.com/pages/errorlogin.php");
}
}
$stmt->close();
$dbc->close();
?>
然后它重定向到表单页面：
<!DOCTYPE HTML>
<?php
session_start();
require ('../../../mysql_connect/mysqli_connect_accounts.php');
require ('../steamauth/steamauth.php');
require ('../steamauth/userInfo.php');
$steamid=$_SESSION['steamid'];
?>
<html>
<head>
<title>TheSkinDealer | Setup</title>
<link rel="stylesheet" type="text/css" href="../css/accept.css"></head><body>
<div id="content">
<div id="acceptbox">
<img src="../images/logo.png">
<form action="setup.php" method="post">
<div id="name1">Full Name:</br> <input type="text" name="fullname"> </br></div>
<div id="name1">TradeURL: <a target="_blank" href="http://steamcommunity.com/id/me/tradeoffers/privacy#trade_offer_access_url">(?)</a></div> <input type="text" name="tradeurl"> </br>
<div id="name1">EMAIL:</div> <input type="text" name="email"> </br>
<div id="checkboxes">
<a href="http://theskindealer.com/tos/tos.php" target="_blank">Terms Of Serice</a>: <input type="checkbox" name="tos" value="1"> </br>
18 Or Older: <input type="checkbox" name="age" value="1"></br>
Newsletter: <input type="checkbox" name="newsletter" value="1"></br>
</div>
<div id="returnhome">
<div id="accept"><input type="submit" value="Create Account"></a></div>
</div>
</form>
</div>
<center><div id="par">Purchases Or Sales Cannot Be Made Without Accepting TOS.</div></center>
</div>
</body>
</html>
最后是插入页面：
<?php
session_start();
require ('../../../mysql_connect/mysqli_connect_accounts.php');
require ('../steamauth/steamauth.php');
require ('../steamauth/userInfo.php');
$steamid=$_SESSION['steamid'];
$insert = "INSERT INTO `".$steamid."` (steam64, freeze, access,
tos, balance, age, email, tradeurl, fullname, newsletter, emailVerified)
VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)";
$stmt = $dbc->prepare($insert);
$stmt->bind_param('sssssssssss',
$steam64,
$freeze,
$access,
$tos,
$balance,
$age,
$email,
$tradeurl,
$fullname,
$newsletter,
$emailVerified
);
$steam64 = $steamid;
$freeze = 0;
$access = 0;
$tos = $_POST["tos"];
$balance = 0.00;
$age = $_POST["age"];
$email = $_POST["email"];
$tradeurl = $_POST["tradeurl"];
$fullname = $_POST["fullname"];
$newsletter = $_POST["newsletter"];
$emailVerified = 0;
$stmt->execute();
header("Location: http://theskindealer.com/");
$stmt->close();
$dbc->close();
?>
【问题讨论】：
-
您是否遇到错误？您应该在您的插入和发布错误语句中设置错误报告。
-
您是否正在为该系统上的每个用户创建一个新的数据库表？这看起来是可扩展的吗？
-
考虑使用
VARCHAR(255)作为默认的通用字符串类型字段，并且只有在您有令人信服的理由时才覆盖它。许多 MySQL 安装会默默地截断任何不适合的数据，从而导致数据丢失、用户投诉和其他严重问题。姓名和电子邮件地址经常出人意料地长，因此适应这些很重要。 -
警告：使用抑制错误的 YOLO 运算符 (
@) 会掩盖代码中的问题，并使此类调试问题变得更加复杂。这是不得已而为之的工具，只能在特殊情况下使用。您应该为用户显示错误消息、记录问题、启动某种重试，或者将所有这些事情结合起来。 -
注意：
mysqli的面向对象接口明显不那么冗长，使代码更易于阅读和审核，并且不容易与过时的mysql_query接口混淆。在您对程序风格投入过多之前，值得转换一下。示例：$db = new mysqli(…)和$db->prepare("…")程序接口是 PHP 4 时代引入的mysqliAPI 的产物，不应在新代码中使用。
标签： php html mysql forms mysqli