【发布时间】:2019-04-01 03:29:54
【问题描述】:
我正在做一个项目,其中每个项目都可以有多个图像,我创建了一个可以接受图像并将它们存储到数组中的表单。问题是每当我尝试将图像插入数据库中的表行时,它都会显示错误:
“数组到字符串的转换”
我该如何解决这个问题?以及如何从同一个数据库表中获取另一个页面上的每个图像。下面是我的代码。
-表单代码
<form method="post" enctype="multipart/form-data" >
<input required type="text" name="name">
<input required type="text" name="location">
<input required type="text" name="status">
<select required name="category">
<option>Category</option>
<option value="construct">Construction</option>
<option value="promgt">Project Development</option>
<option value="archdesign">Architectural Designs</option>
</select>
<textarea required class="form-control" name="descrip" rows="5"></textarea>
<input style="text-align:left" type="file" name="imgs[]" multiple>
<button type="submit" name="submit" formaction="addaction.php">Add Project</button>
</form>
-Addaction.php 代码
<?php
$db=mysqli_connect("localhost","root","dbpassword","dbname");
if(!empty($_FILES['imgs']['name'][0])){
$imgs = $_FILES['imgs'];
$uploaded = array();
$failed = array();
$allowed = array('jpg', 'png');
foreach($imgs['name'] as $position => $img_name){
$img_tmp = $imgs['tmp_name'][$position];
$img_size = $imgs['size'][$position];
$img_error = $imgs['error'][$position];
$img_ext = explode('.',$img_name);
$img_ext = strtolower(end($img_ext));
if(in_array($img_ext, $allowed)) {
if($img_error === 0){
if($img_size <= 500000) {
$img_name_new = uniqid('', true) . '.' . $img_ext;
$img_destination = 'img/'.$img_name_new;
if(move_uploaded_file($img_tmp, $img_destination)){
$uploaded[$position] = $img_destination;
}else{
$failed[$position] = "[{$img_name}] failed to upload";
}
}else{
$failed[$position] = "[{$img_name}] is too large";
}
}else{
$failed[$position] = "[{$img_name}] error";
}
}else{
$failed[$position] = "[{$img_name}] file extension";
}
}
if(!empty($uploaded)){
print_r($uploaded);
}
if(!empty($failed)){
print_r($failed);
}
}
if(isset($_POST['submit'])){
$name = $_POST['name'];
$location = $_POST['location'];
$status = $_POST['status'];
$descrip = $_POST['descrip'];
$category = $_POST['category'];
$img_name_new = $_FILES['imgs']['name'];
if ($db->connect_error){
die ("Connection Failed: " . $db->connect_error);
}
$sql_u = "SELECT * FROM projects WHERE name='$name'";
$sql_e = "SELECT * FROM projects WHERE category='$category'";
$res_u = mysqli_query($db, $sql_u);
$res_e = mysqli_query($db, $sql_e);
if (mysqli_num_rows($res_u) && mysqli_num_rows($res_e) > 0) {
echo "<div style='margin: 0 80px' class='alert alert-danger' role='alert'> Error. Item Already exists </div>";
header("refresh:3 url=add.php");
}else{
$sql_i = "INSERT INTO items (name, location, status, descrip, imgs, category) VALUES ('$name','$location','$status,'$descrip','$img_name_new','$category')";
}
if (mysqli_query($db, $sql_i)){
echo "Project Added Successfully";
}else{
echo mysqli_error($db);
}
$db->close();
}
?>
【问题讨论】:
标签: php arrays database forms mysqli