【发布时间】：2015-11-26 05:25:48
【问题描述】：
我有一个 SQL 数据库，我可以将其拉取并显示在表格视图中。我有一个简单的 PHP 脚本来查询并返回数据库。现在查询变量在 PHP 文件中是硬编码的，但我需要能够从应用程序修改查询。我相信我需要为此使用 http 发布请求。
我已经在下面发布了 PHP 文件和视图控制器文件的全部内容。
首先是 PHP。
<?php
$config = parse_ini_file("config_files/config.ini");
// Create connection
$con=mysqli_connect("localhost",$config["username"],$config["password"],$config["dbname"]);
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// This added as my attempt to do POST. Before I just had 9 in the query where I have the variable $user_id_app_sent_int.
$user_id_app_sent = $_REQUEST['user_id_app'];
// I did this (int) conversion because I think it is receiving form the app as a string?
$user_id_app_sent_int = (int)$user_id_app_sent;
$sql = "SELECT * FROM `invoice` WHERE `user_id` = $user_id_app_sent_int";
// Check if there are results
if ($result = mysqli_query($con, $sql))
{
// If so, then create a results array and a temporary one
// to hold the data
$resultArray = array();
$tempArray = array();
// Loop through each row in the result set
while($row = $result->fetch_object())
{
// Add each row into our results array
$tempArray = $row;
array_push($resultArray, $tempArray);
}
// Finally, encode the array to JSON and output the results
echo json_encode($resultArray);
}
// Close connections
mysqli_close($con);
?>
现在是 swift 文件。
import UIKit
class InvoiceListViewController: UIViewController, UITableViewDelegate {
// Custom Variable
var invoiceData = [NSDictionary]()
var arrayCount = Int()
// Table View Outlet
@IBOutlet weak var tableView: UITableView!
override func viewDidLoad() {
super.viewDidLoad()
// This is the main pull data section.
let url = NSURL(string: "http://localhost:8888/service.php")!
let task = NSURLSession.sharedSession().dataTaskWithURL(url) { (data, response, error) -> Void in
// This is my attempt.
let request = NSMutableURLRequest(URL: NSURL(string: "http://localhost:8888/service.php")!)
request.HTTPMethod = "POST"
let postString = "user_id_app=9"
request.HTTPBody = postString.dataUsingEncoding(NSUTF8StringEncoding)
let task = NSURLSession.sharedSession().dataTaskWithRequest(request) {
data, response, error in
if error != nil {
print("error=\(error)")
return
}
print("response = \(response)")
}
task.resume()
// end post test attempt. If this section is removed, and I return the hardcoded value to the PHP file, it works fine for pulling and displaying the database data.
if let invoiceWebData = data{ // Open if let
do {
let invoiceDataPulled = try NSJSONSerialization.JSONObjectWithData(invoiceWebData, options: NSJSONReadingOptions.MutableContainers) as! [NSDictionary]
self.invoiceData = invoiceDataPulled
self.arrayCount = self.invoiceData.count
dispatch_async(dispatch_get_main_queue(), { () -> Void in
self.tableView.reloadData()
})
} // Close Do
catch {
print("JSON Serialization Failed")
}
} // Close If Let
} // Close Task
task.resume()
} // Close View Did Load
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
print(invoiceData)
return arrayCount
}
func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCellWithIdentifier("invoiceCell") as! InvoiceCell
let row = indexPath.row
let rowData: NSDictionary = invoiceData[row]
let userLogIn: String? = (rowData["user_id"] as? String)
if let logInUnwrapped = userLogIn {
cell.cellNameLabel.text = logInUnwrapped
}
return cell
}
}
所以基本上，我想发送一个查询变量来进行 PHP 文件查询并返回数据库的特定部分。
【问题讨论】：
-
实际上，我检查了您的代码，您的 PHP 部分似乎还不错。究竟什么不起作用？您是否将数据接收到 $_REQUEST 中？
-
我认为我的 Swift 方面可能是错误的。看看我说的部分 // 这是我的尝试。
-
你应该使用下面的代码来看看你到底收到了什么
-
我尝试了这两种方法，但我看不到任何结果。从 Xcode 我在控制台中得到以下内容，这是 'response' response = Optional(
-
实际上你应该打开与你的 php 文件相同级别的 log.txt 以查看你的应用程序发送了哪些数据。你能把输出粘贴到这里吗？