格式化 json 数据。如何合并具有与键相同值的json数组？

Question

对不起，如果我的问题有点令人困惑。 以下是我的 json 输出形式 mysql：

[{"ID":"2","BatchID":"0","Day":"Sunday","Low":"01:15","High":"02.45","Mid":    "01:30 01:45 02:00 02:15 02:30"},    {"ID":"1","BatchID":"0","Day":"Sunday","Low":"00.45","High":"00:30","Mid":"    01:30 01:45 02:00 02:15 02:30"}]

在这种情况下，我想使用“星期日”这一天来合并两个对象以形成如下内容：

"Sunday":[
        {
            "low":"00:15",
            "high":"00.45",
            "mid":["00:30"]
        },
        {
            "low":"01:15",
            "high":"02.45",
            "mid":["01:30","01:45","02:00","02:15","02:30"]
        }

    ]

另外，有没有什么工具可以帮助我在 php 中制作模型以将其保存在数据库中？

提前致谢。

最大

Answer 1

您可以按照其他答案的建议在 PHP 中重新组织它。你也可以用 Javascript 重新组织它：

var values = [{"ID":"2","BatchID":"0","Day":"Sunday","Low":"01:15","High":"02.45","Mid":    "01:30 01:45 02:00 02:15 02:30"},    {"ID":"1","BatchID":"0","Day":"Sunday","Low":"00.45","High":"00:30","Mid":"    01:30 01:45 02:00 02:15 02:30"}];

var final = {};
values.forEach(function(element, index, array) {
    if (!final[element.Day]) 
        final[element.Day] = [];

    final[element.Day].push(
        {
            "low": element.Low,
            "high": element.High,
            "mid": element.Mid.split(" ")
        }
    );
});

Answer 2

你可以使用类似的东西：

$data = json_decode($mysql_data, true);
$res = [];
foreach ($data as $d)
{
    $add = ['low'  => $d['Low'],
            'high' => $d['High'],
            'mid'  => explode(' ', trim($d['Mid']))];
    if (!isset($res[$d['Day']]))
        $res[$d['Day']] = $add;
    else
        $res[$d['Day']][] = $add;
}
$pretty_data = json_encode($res);