【发布时间】:2021-12-08 07:57:32
【问题描述】:
当我使用 $this->form_validation->set_rules 在控制器中设置规则时,我无法弄清楚为什么我在 php 日志中收到错误“无法找到验证规则”。
这是我在视图中的代码:
<div id="yearDiv" class="form-group">
<div class="form-group">
<label for="yearList">Study Years</label>
<input type="text" class="form-control" id="yearList">
</div>
<div class="form-group row">
<div class="col-md-2">
<label for="startYearBox">Start Year</label>
<input type="text" class="form-control" id="startYearBox">
</div>
<div class="col-md-2">
<label for="endYearBox">End Year</label>
<input type="text" class="form-control" id="endYearBox">
</div>
<div class="col-md-8"><small>(Use present for End Year if study is ongoing.)</small>
</div>
</div>
</div>
<script type='text/javascript'>
var data = {};
data['years']={};
data['years']['intStartYr']= $('#startYearBox').val();
data['years']['intEndYr']= $('#endYearBox').val();
var posturl = '<?php echo site_url('manage/climate_indicators/updateStudyYears');?>'
$.when($.ajax({type: "POST", url: posturl, data:data, dataType: 'json'})).done(function(result) {
console.log(result.status);
});
</script>
还有我在控制器中的 php 代码:
public function updateStudyYears() {
if (!$this->input->post() OR !$this->input->is_ajax_request() ){
echo json_encode(array('status'=>'failed','errors'=>array('Access Mode'=>'Disallowed')));
exit();
}
else {
$postData = $this->input->post(NULL, true);
$yearArray = $postData['years'];
if(empty($yearArray)) {
echo json_encode(array('status'=>'failed', 'errors'=>'Years are empty'));
exit();
}
$this->form_validation->set_rules('years[intStartYr]', 'Start Year', 'required',
array('required' => 'Start year must have a valid year.'));
$this->form_validation->set_rules('years[intEndYr]', 'End Year', 'required',
array('required' => 'End year must have a valid year.'));
if ($this->form_validation->run() === FALSE) {
$validationErrs = $this->form_validation->error_array();
echo json_encode(array('status'=>'form-errors', 'valErrs'=>$validationErrs));
exit;
}
else {
$status = $this->climate_indicators_model->setStudyYears($yearArray);
if ($status) {
echo json_encode(array('status'=>'success', 'message'=>'Study year information successfully updated.'));
}
else echo json_encode(array('status'=>'failed', 'errors'=>'Db error on update'));
}
exit();
}
}
</script>
感谢您的帮助!如果您还有其他问题,请告诉我
【问题讨论】:
-
您的意见是什么?我尝试使用您的代码,但没有显示该错误?
标签: php codeigniter codeigniter-3