【问题标题】:Query database in helper file Codeigniter 3在帮助文件 Codeigniter 3 中查询数据库
【发布时间】:2015-12-04 04:15:33
【问题描述】:

我试图向帮助文件中添加一个函数以从 Db 收集额外的信息。这出现了错误,因为我试图用来调用函数的文档 ID 作为数组而不是我想要的......

我的模型如下所示:

public function get_categoryads()
{

    $this->db->select('ads.id AS id, ads.userid AS userid, ads.adnr AS adnr,
  ads.location AS town, search_town.townFileName AS townlink, search_prov.provLabel AS province, 
  search_prov.subLink AS provlink,text, ad_image.image AS image,addate, r_option, R_rand,
  adcat.name AS catname,  adcat.clinkname AS clinkname, adsubcat.name AS subcatname, adsubcat.linkname AS subcatlink,
  adcat.id AS catid, adsubcat.id AS subcatid, ads.r_option AS r_option, ads.R_rand AS R_rand, 
  adcat.catcol1 AS catcol1, adcat.catcol2 AS catcol2, search_town.townId,ads.townId');
  $this->db->from('ads');
  $this->db->join('adsubcat', 'adsubcat.id=ads.subcatid');
  $this->db->join('adcat', 'adcat.id=ads.catid');
  $this->db->join('search_town', 'search_town.townId=ads.townId');
  $this->db->join('search_region', 'search_region.regionId=search_town.relRegionId');
  $this->db->join('search_prov', 'search_prov.provId=search_region.relProvId');
  $this->db->join('ad_image', 'ad_image.adid=ads.id');
  $array = array(
  'ad_image.picorder'=> 1,
  'ad_image.aproved'=> 1,
    'adcat.id' => 9,
   'scam' => 0,
    'adactive' => 1
    );

  $this->db->where($array);
  $this->db->group_by("ads.id");
  $this->db->order_by('addate','desc');
  $this->db->limit(5); 
  $query = $this->db->get(); 
  return $query->result_array();
}

我的控制器如下所示:

class Categories extends CI_Controller {
          public function __construct()
          {
                parent::__construct();
                $this->load->model('categorylist_model');
                $this->load->helper('text');
          }
            public function index()
            {
            $this->load->helper('url');
            $data = array('sitename'=>'Title', 'page_title' => 'Categories');
          $data['categories'] = $this->categorylist_model->get_categoryads();
          $this->load->view('templates/header', $data);
            $this->load->view('templates/navbar');
            $this->load->view('templates/breadcrumbs');
            //$this->load->view('templates/category_selector');
            $this->load->view('content_categories');
            $this->load->view('templates/footer');
          }
}

我现在不确定如何将额外的查询添加到控制器?还是应该将其添加到模型本身以及如何添加?

我尝试将功能添加到控制器如下(不正确):

class Categories extends CI_Controller {
          public function __construct()
          {
                parent::__construct();
                $this->load->model('categorylist_model');
                $this->load->helper('text');
          }
            public function index()
            {
            $this->load->helper('url');
            $data = array('sitename'=>'Title', 'page_title' => 'Categories');
          $data['categories'] = $this->categorylist_model->get_categoryads();
          $this->load->view('templates/header', $data);
            $this->load->view('templates/navbar');
            $this->load->view('templates/breadcrumbs');
            //$this->load->view('templates/category_selector');
            $this->load->view('content_categories');
            $this->load->view('templates/footer');
          }
          public function tLink( $aid ) {  
          $ci=& get_instance();
          $ci->load->database(); 

          $sql ="SELECT adfields.f_value AS fvalue FROM adfields
                JOIN field_name ON field_name.id=adfields.f_id
                WHERE adid='$aid' GROUP BY adfields.f_id ORDER BY field_name.keyf ASC"; 

          $query = $ci->db->query($sql);
          $row = $query->row();
          return $row->fvalue;
          }

}

并在 with tLink($adid) 中调用它,但给了我致命错误:调用未定义函数 tLink()

【问题讨论】:

  • 你加载你的帮助文件了吗???
  • 确实如此。使用当前函数,我收到以下错误:遇到 PHP 错误严重性:通知消息:数组到字符串转换
  • 也发布您的查看代码
  • 我用 $this->load->helper('list'); 调用了 list_helper.php;它从我的模态中获取 $id 并通过
  • 从控制器输入一些代码

标签: php mysql codeigniter codeigniter-3


【解决方案1】:

您在 cmets 中提到的 PHP 错误是正确的,要么是:

  • 传递$aid 的数组而不是字符串 例如,您通过array( 0 => 45 ) 而不是45

  • 尝试echo 结果,这是一个array/object。相反,请使用 Code Igniter 的 row() 命令,然后选择您需要的结果。


function tLink( $aid ) {  
    $ci=& get_instance();
    $ci->load->database(); 

    $sql ="SELECT adfields.f_value AS fvalue FROM adfields
          JOIN field_name ON field_name.id=adfields.f_id
          WHERE adid='$aid' GROUP BY adfields.f_id ORDER BY field_name.keyf ASC"; 

    $query = $ci->db->query($sql);
    $row = $query->row();
    return $row->fvalue;
}

最后,最好在 Controller 中加载这个模型,而不是在 helper 处要求它(通常用于视图函数)

/**
 *
**/
class Link_model extends CI_Model { 

    public function getLink( $aid ) { 
          $sql ="SELECT adfields.f_value AS fvalue FROM adfields
                 JOIN field_name ON field_name.id=adfields.f_id
                 WHERE adid='$aid' GROUP BY adfields.f_id ORDER BY
                 field_name.keyf ASC"; 

         $query = $ci->db->query($sql);
         $row = $query->row();
         return $row->fvalue;
    }
}

/**
 *
**/
class Categories extends CI_Controller {

    public function index() {
        $this->load->model( 'Link_model' );

        $categories = array();
        $getCategoryIds = $this->categorylist_model->get_categoryads();

        foreach( $getCategoryIds as $aid ){
             $categories = array(
                 "id"   => $aid,
                 "link" => $this->link_model->getLink( $aid )
             );
        }

        $data = array(
            "categories" => $categories
        );

        $this->load->view('templates/header', $data );
    }

}

现在终于在你看来:

<div class="container">
    <?php if ( isset( $categories ) && count( $categories ) > 0 ): ?>
        <?php foreach( $categories as $category ): ?>
            <?=( $category["link"] )?>
        <?php endforeach; ?>
    <?php endif; ?>
</div>

【讨论】:

  • 感谢您提供更详细的解释...但是,在我看来,如果我调用 $this->load->model('categorylist_model');在控制器中填充视图,如何获取 Id 的句柄以传递给 Link_Model 类?此外,这些结果通常由 3 - 4 行组成?我确实编辑了我原来的问题,试图让它更能理解我想要实现的目标......(除了试图了解如何使用 Codeigniter 和 OOP PhP,因为我来自程序编码背景)
  • 您将在控制器中构建视图所需的一切。遍历您返回的每个 ID 并获取每个 ID 的链接。如果您已经在视图中查询模型,那么您已经在 CodeIgnitier 的设计中做错了。 $this-&gt;categorylist_model-&gt;get_categoryads(); 包含的 ID 正确吗?
  • @Howzit 再次查看我编辑的答案,希望它能给你一个想法! x) 如果没有,请道歉!
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