在php中计算带有条件的关联数组[重复]答案

【问题标题】：Count associative array with condition in php [duplicate]在php中计算带有条件的关联数组[重复]
【发布时间】：2021-09-09 21:22:08
【问题描述】：

我正在使用 php，我有关联数组，我想计算总数键为“IsRatingQuestion”且值为 =“1”的数组（使用循环）数这是我的数组

Array
(
    [0] => Array
        (
            [ques_id] => 2
            [question] => Please enter your mobile number.
            [IsRatingQuestion] => 0
            [ISSubQuestion] => 
            )

    [1] => Array
        (
            [ques_id] => 2
            [question] => Lorem Ipsum dummy text
            [IsRatingQuestion] => 
            [ISSubQuestion] => 
            )

    [2] => Array
        (
            [ques_id] => 15
            [question] => Would your recommend TOSSIN ?
            [IsRatingQuestion] => 1
            [ISSubQuestion] => 
            )

    [3] => Array
        (
            [ques_id] => 18
            [question] => which type of mobile you have ?
            [IsRatingQuestion] =>1 
            [ISSubQuestion] => 1
            )

这是我的 php 代码（现在计算所有记录/数组），我想计算键为“IsRatingQuestion”且值为 =“1”的数组，我该怎么做？提前致谢。

<?php   
    $count=count($rec);
    for ($j = "2"; $j < $count+"1"; $j++)
                        {
?>
    <li>Step <?php echo $j; ?></li>
<?php } ?>

【问题讨论】：

标签： php arrays loops

【解决方案1】：

你可以使用array_filter函数来过滤IsRatingQuestion=1的项目

$filterdArray = array_filter($rec,function($item){
    if($item['IsRatingQuestion']==1){
        return $item;
    }
});
count($filterdArray)

【讨论】：

【解决方案2】：

您可以保留一个计数器，遍历数组，当条件为真时，添加到计数器中。

$count = 0;
foreach($entries as $entry) {
    if (isset($entry['isRatingQuestion']) && $entry['isRatingQuestion'] === 1) {
        $count ++;
    }
}
echo "$count entries match the condition";

【讨论】：

【解决方案3】：

遍历数组，检查它是否等于 1，如果它确实添加到您的计数器；示例：

$count = 0;
foreach($yourArray as $val){
    if(isset($val['isRatingQuestion']) && $val['IsRatingQuestion'] === 1){
        $count++;
    }
}
echo $count;
# Output: 2

【讨论】：