在 php/Joomla 中创建复选框过滤器

Question

首先，我必须告诉你，我在这方面的经验很少。我遇到的问题是我正在尝试将 Joomla 生成的网站重新编码为将复选框显示为过滤器。现在我正在使用一个有效的多选列表，但我需要有复选框（这样用户在选择多个值时不需要按住 Shift 或 Ctrl）。有两个过滤器（一个用于州，另一个用于城市），城市的过滤器选项是根据州过滤器中的选择生成的。我不知道如何将所有内容都变成复选框，从而根据“州”区域中的复选框继续生成“城市复选框”...

public static function makeStateList($req_country_id,$req_state_id,$name,$onChange,$firstOption,$style,$class="input-medium"){
        global $configClass,$languages;
        $db = JFactory::getDbo();
        $stateArr = array();
        $show_available_states_cities = $configClass['show_available_states_cities'];

        $lgs = OSPHelper::getLanguages();
        $translatable = JLanguageMultilang::isEnabled() && count($lgs);
        $suffix = "";
        if($translatable){
            $suffix = OSPHelper::getFieldSuffix();
        }

        if((!HelperOspropertyCommon::checkCountry()) or ($req_country_id > 0)){

            $query  = "Select id as value,state_name".$suffix." as text from #__osrs_states where published = 1 ";
            if($req_country_id > 0){
                $query .= " and country_id = '$req_country_id'";
            }else{
                $query .= " and country_id = '".$configClass['show_country_id']."'";
            }
            if($show_available_states_cities == 1){
                $query .= " and id in (Select state from #__osrs_properties where approved = '1' and published = '1')";
            }
            $query .= " order by state_name";
            $db->setQuery($query);
            $states = $db->loadObjectList();
            if($firstOption != ""){
                $stateArr[] = JHTML::_('select.option','',$firstOption);
                $stateArr   = array_merge($stateArr,$states);
            }else{
                $stateArr   = $states;
            }



        return JHTML::_('select.genericlist',$stateArr,$name,'class="'.$class.'" multiple="multiple" '.$onChange.' '.$style,'value','text',$req_state_id);


        }else{
            $stateArr[] = JHTML::_('select.option','',$firstOption);
            return JHTML::_('select.genericlist',$stateArr,$name,'class="'.$class.'" disabled','value','text');
        }
    }


    /**
     * Load City
     *
     * @param unknown_type $option
     * @param unknown_type $state_id
     * @param unknown_type $city_id
     * @return unknown
     */
    public static function loadCity($option,$state_id,$city_id,$class="input-medium"){
        global $mainframe,$configClass,$languages;
        $db = JFactory::getDBO();

        $lgs = OSPHelper::getLanguages();
        $translatable = JLanguageMultilang::isEnabled() && count($lgs);
        $suffix = "";
        if($translatable){
            $suffix = OSPHelper::getFieldSuffix();
        }

        $availSql = "";
        $show_available_states_cities = $configClass['show_available_states_cities'];
        $cityArr = array();
        $cityArr[]= JHTML::_('select.option','',JText::_('OS_ALL_CITIES'));
        if($state_id > 0){
            if($show_available_states_cities == 1){
                $availSql = " and id in (Select city from #__osrs_properties where approved = '1' and published = '1')";
            }
            $db->setQuery("Select id as value, city".$suffix." as text from #__osrs_cities where  published = '1' $availSql and state_id = '$state_id' order by city");

            $cities = $db->loadObjectList();
            $cityArr   = array_merge($cityArr,$cities);
            $disabled  = "";
        }else{
            $disabled  = "disabled";
        }
        return JHTML::_('select.genericlist',$cityArr,'city','class="'.$class.'" '.$disabled,'value','text',$city_id);
    }

抱歉，帖子太长了。我希望这是有道理的...感谢您的所有帮助！

Answer 1

您基本上必须遍历您的数组（$stateArr 和 $cityArr）并输出复选框，而不是使用内置的 html 帮助程序 JHTML::_('select.genericlist',$cityArr ... 在每个这两个函数，无论在哪里使用 JHTML 来生成选择列表，都将其替换为：

foreach($stateArr as $key=>$value){
  echo "<div><input type='checkbox' name='$name' 
  value='{$key}' />{$value}</div>"; 
}

您可能需要处理某些情况，例如某些框已被选中等。