【发布时间】:2015-02-22 01:08:15
【问题描述】:
好的,我正在尝试使用文本字段和复选框将一些数据插入到 mySQL 中。我将文本字段转到一个表,将复选框转到另一个表。我可以将数据插入到两个表中,但我试图让我的第二个复选框根据选择的部门将数据插入可见列。我的想法是隐藏 department-checkBoxes[] 并显示 visible-checkBoxes[],只要我可以获得要插入的 visible-checkBoxes[] 数据。
mySQL 表
id | departments_fk | qsps_fk | visible
270 | 1 | 218 | 0
271 | 22 | 218 | 0
272 | 1 | 219 | 0
273 | 22 | 219 | 0
274 | 1 | 220 | 0
275 | 22 | 220 | 0
这是我的表格。
<form action="create-qsp.php" method="post">
<div class="qsp-name">QSP Name:
<input type="text" name="qsp_name" class="name-box" value="" />
</div>
<div class="rev">QSP Rev:
<input type="text" name="qsp_rev" class="rev-box" value="" />
</div>
<div class="qsp-departments">Department:</div>
<div class='department-checkBoxes'>
<label class='checkBoxes'>
<?php $qsp_department_list = find_all_departments();
while($qsp_department = mysqli_fetch_assoc($qsp_department_list)) { global $visible;?>
<div class='department-check'>
<input type='checkbox' name='department-checkBoxes[]' value='
<?php echo htmlentities($qsp_department["id"]); ?>
' checked='checked' />
<input type='checkbox' name='visible-checkBoxes[]' value='1' />
<?php echo htmlentities($qsp_department["department_name"]); ?>
</div>
<?php }
mysqli_free_result($qsp_department_list); ?>
</label>
</div>
<div class="create-btn">
<input type="submit" name="submit" value="Create QSP" />
</div>
</form>
这是我的部门复选框 [] 的 PHP
$qsps_id = mysqli_insert_id($db_connection);
$departments_id = $_POST["department-checkBoxes"];
$visible_id = $_POST["visible-checkBoxes"];
if(isset($_POST['department-checkBoxes'])) {
foreach ($departments_id as $id){
$query1 = "INSERT INTO junction_departments_qsps (departments_fk, qsps_fk) VALUES ($id, $qsps_id) ";
$result1 = mysqli_query($db_connection, $query1);
}
}
这是我的可见复选框 [] 的 PHP
if(isset($_POST['visible-checkBoxes'])) {
foreach ($visible_id as $id){
$query2 = "INSERT INTO junction_departments_qsps (qsps_fk, visible) VALUES ($qsps_id, $id) ";
$result2 = mysqli_query($db_connection, $query2);
}
}
感谢您的帮助!
【问题讨论】:
-
为什么不使用 if 语句然后基于它创建查询?