【发布时间】:2011-08-18 22:53:23
【问题描述】:
【问题讨论】:
标签: php datetime date timestamp
【问题讨论】:
标签: php datetime date timestamp
$timestamp1 = x;
$timestamp2 = y;
$days_elapsed = floor(($timestamp2 - $timestamp1)/86400);
echo $days_elapsed;
【讨论】:
Convert them to UNIX-timestamp(如果他们还没有),那么就
$diff = abs($timestamp1 - $timestamp2);
$days = (int) ($diff / 60 / 60 / 24);
【讨论】:
这样的事情应该可以解决问题:$days = (strtotime($timestamp1)-strtotime($timestamp2))/(60*60*24);
【讨论】:
这段代码应该可以解决问题
$numDays = abs($timeOne - $timeTwo)/60/60/24;
【讨论】: