在php中定义数组数组[重复]答案

【问题标题】：Defining an array of array in php [duplicate]在php中定义数组数组[重复]
【发布时间】：2016-02-08 12:21:57
【问题描述】：

我在php中定义了一个这样的数组

<?php

$Category = array("Apparel","Grocery","Health","Gift","Footwear","Jewelry","Food & Bev");
$Shops = array("Giny & Jony","Big Bazaar","Health & Glow","Factory Outlet Store","Archies","Bata","100 Rs Shop","Silver Touch","Sri Devi Traders","Avatar","Steamzz");
$Type = array($Category,$Shops); 

echo $Type[0];


?>

当我尝试打印时，它显示“错误：无法将数组转换为字符串” 这种声明方式正确吗？？如果没有，你能分享你的看法吗？

【问题讨论】：

你认为$Type[0]包含什么？
使用 for 循环代替打印.. 或 var_dump()
在处理数组时应该始终使用 print_r
Var_dump 给出了类似的结果stackoverflow.com/questions/3406171/php-var-dump-vs-print-r

标签： php arrays

【解决方案1】：

它不能回显$Type[0]，因为它是一个数组。可以使用print_r() 打印数组。

$Category = array("Apparel","Grocery","Health","Gift","Footwear","Jewelry","Food & Bev");
$Shops = array("Giny & Jony","Big Bazaar","Health & Glow","Factory Outlet Store","Archies","Bata","100 Rs Shop","Silver Touch","Sri Devi Traders","Avatar","Steamzz");
$Type = array($Category,$Shops); 

print_r($Type[0]);

【讨论】：

感谢分享。 @泰莉

【解决方案2】：

如果你想调试你的变量，看看它们是什么样子，一个简单的解决方案可能是var_dumpem。

var_dump($Type[0]);

但你没有做错任何事，只是你不能回显array 这是一个合法的打印声明作为例子。

echo $Type[0][0];

【讨论】：

【解决方案3】：

试试看结果-

<?php

$Category = array("Apparel","Grocery","Health","Gift","Footwear","Jewelry","Food & Bev");
$Shops = array("Giny & Jony","Big Bazaar","Health & Glow","Factory Outlet Store","Archies","Bata","100 Rs Shop","Silver Touch","Sri Devi Traders","Avatar","Steamzz");
$Type = array($Category,$Shops); 

var_dump($Type);


?>

【讨论】：