将数组解析为字符串

Question

我有一个包含键值的对象数组

Array ( [0] =>stdClass Object ( [privacy] => {"name": "on", "email": null, "mobile": null, "address": "on", "alt_contact": "on"} ) )

我需要打印一个字符串，其中包含逗号分隔的键，其值为“on”。结果字符串应该是

$result = "name,address,alt_contact"; 

请帮忙

Answer 1

这对你有用..

$json = '{"name": "on", "email": null, "mobile": null, "address": "on", "alt_contact": "on"}';
$array = json_decode($json,true);

$str = "";
foreach($array as $key=>$value)
{
    if($value == "on")
        $str .= $key.",";
}
return rtrim($str,",");

结果：- 姓名、地址、alt_contact

Answer 2

这是您的请求转换为 PHP 的方式：

我需要

• 打印 - echo()
• 将包含逗号分隔的字符串 - implode()
• 值为“on”的键 - array_keys()

这是代码，直接来自上面的列表：

$json = '{"name": "on", "email": null, "mobile": null, "address": "on", "alt_contact": "on"}';
// Pass TRUE as second argument to get arrays back; stdObject is useless
$data = json_decode($json, TRUE);

// print comma separated keys of 'on'
echo(implode(',', array_keys($data, 'on')));

Answer 3

感谢 Jaimin，它有帮助

必须将 $privacy 对象解析为数组

$userPrivacies = $userPrivacies[0]->privacy;

并稍后使用您的代码。

所以解决方案变成了

$userPrivacies = $userPrivacies[0]->privacy;

$array = json_decode($userPrivacies,true);

$str = "";
foreach($array as $key=>$value)
{
   if($value == "on")
      $str .= $key.",";
}
echo rtrim($str,",");