如何向另一个 PHP 网站的 AJAX POST 方法发送参数并获取 JSON 信息

Question

我正在研究“如何解析来自其他网站的内容”。我正在使用 HTML DOM 解析 来获取信息。我面临的问题是包含 AJAX POST 调用以获取信息的网站。示例网站：Massachussets

1.这里使用ajax post方式获取医生信息

Request URL:http://www.massgeneral.org/assets/javascripts/facets/doctors/doctors.ashx
Request Method:POST

如何将参数传递给此处的发布方法？我尝试的是

<?php
echo '<center><h3>Massachusetts Information</h3></center>';
// extra headers
//$headers[]= "Accept-Encoding: gzip, deflate";
$fields['center'] = "";
$fields['centerPreSelected'] = false;
//$fields['displayPaging'] = false;
$fields['gender'] = "";
$fields['isEmpty'] = true;
$fields['languages'] = [];
$fields['letter'] = "A";
$fields['letter'] = "";
$fields['locations'] = array();
$fields['numberOfPages'] = 15;
$fields['numberPerPage'] = 50;
$fields['page'] = 1;
$fields['program'] = "";
$fields['range'] = array('Item1' => 0,'Item2' => 49);
$fields['saytLimit'] = "20";
$fields['term'] = "";

$POSTFIELDS = http_build_query($fields);

$headers[] = "Accept: application/json, text/plain, */*";
$headers[] = "Accept-Encoding: gzip, deflate";
$headers[] = "Accept-Language: en-GB,en;q=0.5";
$headers[] = "Connection: keep-alive";
$headers[] = "Content-Type: application/json";
$headers[] = "Host: www.massgeneral.org";
$headers[]="Referer: http://www.massgeneral.org/doctors/";

$login_submit_url = "http://www.massgeneral.org/assets/javascripts/facets/doctors/doctors.ashx";
$ch = curl_init();
curl_setopt($ch, CURLOPT_HEADER,  0);
curl_setopt($ch, CURLOPT_USERAGENT, $agent);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);

curl_setopt($ch, CURLOPT_URL, $login_submit_url);
curl_setopt($ch, CURLOPT_HTTPHEADER,  $headers);
curl_setopt($ch, CURLOPT_VERBOSE, true);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $POSTFIELDS);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 0);
$result = curl_exec($ch);

echo $result;

它没有获取医生信息。 请提供链接或想法来解析它。

Answer 1

您正在使用http_build_query() 创建“foo=1&bar=2”样式格式。该站点需要 json，因此您想改用 json_encode()。

此外，请忽略 gzip 标头，除非您确定确实要处理 gzip 压缩响应。