【发布时间】:2018-02-22 05:36:38
【问题描述】:
我正在使用 lxml 报废数据
这是单个帖子的检查元素
<article id="post-4855" class="post-4855 post type-post status-publish format-standard hentry category-uncategorized">
<header class="entry-header">
<h1 class="entry-title"><a href="http://aitplacements.com/uncategorized/cybage/" rel="bookmark">Cybage..</a></h1>
<div class="entry-meta">
<span class="byline"> Posted by <span class="author vcard"><a class="url fn n" href="http://aitplacements.com/author/tpoait/">TPO</a></span></span><span class="posted-on"> on <a href="http://aitplacements.com/uncategorized/cybage/" rel="bookmark"><time class="entry-date published updated" datetime="2017-09-13T11:02:32+00:00">September 13, 2017</time></a></span><span class="comments-link"> with <a href="http://aitplacements.com/uncategorized/cybage/#respond">0 Comment</a></span> </div><!-- .entry-meta -->
</header><!-- .entry-header -->
<div class="entry-content">
<p>cybage placement details shared <a href="http://aitplacements.com/uncategorized/cybage/" class="read-more">READ MORE</a></p>
</div><!-- .entry-content -->
对于每个这样的帖子,我想提取标题、帖子内容和发布时间。
例如上面的,细节将是
{title : "Cybage..",
post : "cybage placement details shared"
datetime="2017-09-13T11:02:32+00:00"
}
到目前为止,我能够实现的目标: 该网站需要登录,我已成功登录。
提取信息:
headers = {'User-Agent': 'Mozilla/5.0 (X11; Linux x86_64)
Chrome/42.0.2311.90'}
url = 'http://aitplacements.com/news/'
page = requests.get(url,headers=headers)
doc = html.fromstring(page.content)
#print doc # it prints <Element html at 0x7f59c38d2260>
raw_title = doc.xpath('//h1[@class="entry-title"]/a/@href/text()')
print raw_title
raw_title 给出空值[] ?
我做错了什么?
【问题讨论】:
-
你应该看看beautiful soup。它非常适合您的需要。或者
scrapy,如果您需要更高级的东西(例如,蜘蛛)。 -
我得到了空值,因为我被注销了,解决了这个问题
标签: python html-parsing lxml