【发布时间】:2011-10-13 02:09:56
【问题描述】:
我是 iPhone 开发的新手,我正在尝试解析此链接并将其放在我的 tableview 上,但是当我的 tableview 显示时,标题不会显示在行中。我在这里做错了什么?
- (void)viewDidLoad {
[super viewDidLoad];
self.title = @"RSS Feeds";
rssList = [[NSMutableArray alloc] initWithCapacity:1];
NSString *URLString = [[NSString alloc]initWithFormat:@"http://www.rpg.net/index.xml"];
NSLog(@"%@",URLString);
NSURL *xmlURL = [NSURL URLWithString:URLString];
NSXMLParser *firstParser = [[NSXMLParser alloc] initWithContentsOfURL:xmlURL];
[firstParser setDelegate:self];
[firstParser parse];
[URLString release];
}
- (void)parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qualifiedName attributes:(NSDictionary *)attributeDict {
if ([elementName compare:@"item"] == NSOrderedSame) {
[rssList addObject:[[NSDictionary alloc] initWithObjectsAndKeys:
[attributeDict objectForKey:@"title"],@"title",
[attributeDict objectForKey:@"link"],@"link",
nil]];
}
}
【问题讨论】:
-
您是否实现了
UITableViewDataSource协议以返回一个使用rssList中的元素格式化的单元格? -
先检查解析是否正常
标签: iphone xml ios4 xml-parsing