【问题标题】:Alter the element, if particular element not found as its descendant如果未找到特定元素作为其后代,则更改元素
【发布时间】:2014-10-08 06:34:55
【问题描述】:

请提出建议。如果元素“mfenced”没有像“munderover”或“mfrac”这样的元素作为其后代,则需要将其更改为元素“mo”。 在 xml 中找到“text1”和“text2”文本,在这些区域我的代码无法更改为“mo”。

输入 XML:

    <article>
    <math>
        <mi>P</mi>
        <mfenced open="(" close=")"><!--To be changed to 'mo', bcs 'mfenced' not having mfrac or munderover as its descendant-->
            <mi>g</mi>
        </mfenced>
        <mfenced open="[" close="]"><!--To be retained as it is, bcs, mfenced having either mfrac or munderover as its descendant-->
            <mfenced open="(" close=")"><!--To be retained as it is, bcs, mfenced having either mfrac or munderover as its descendant-->
                <mi>g</mi>
                <mo>=</mo>
                <munderover>
                    <mrow><mn>1</mn></mrow>
                    <mfenced open="(" close=")"><!--To be changed to 'mo', bcs 'mfenced' not having mfrac or munderover as its descendant-->
                        <mrow><mi>text1</mi></mrow>
                    </mfenced>
                    <mrow><mi>N</mi></mrow>
                </munderover>
            </mfenced>
            <mi>N</mi>
        </mfenced>
        <mfenced open="[" close="]"><!--To be retained as it is, bcs, mfenced having either mfrac or munderover as its descendant-->
            <mfenced open="(" close=")"><!--To be retained as it is, bcs, mfenced having either mfrac or munderover as its descendant-->
                <mfrac>
                    <mrow>
                        <mfenced open="(" close=")"><!--To be changed to 'mo', bcs not having mfrac or munderover as its descendant-->
                            <mi>text2</mi>
                        </mfenced>
                    </mrow>
                    <mrow><mo>2</mo></mrow>
                </mfrac>
            </mfenced>
        </mfenced>
    </math>
</article>

XSLT:

    <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node() | @*">
    <xsl:copy>
        <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
</xsl:template>
<xsl:template match="mfenced">
    <xsl:choose>
        <xsl:when test="descendant::mfrac|descendant::munderover">
                <xsl:copy-of select="."/>
        </xsl:when>
        <xsl:otherwise>
            <xsl:element name="mo">
                <xsl:value-of select="@open"/>
            </xsl:element>
            <xsl:apply-templates/>
            <xsl:element name="mo">
                <xsl:value-of select="@close"/>
            </xsl:element>
        </xsl:otherwise>
    </xsl:choose>
</xsl:template>
<xsl:template match="//comment"/>
</xsl:stylesheet>

要求的结果:

    <article>
   <math>
      <mi>P</mi>
      <mo>(</mo>
        <mi>g</mi>
      <mo>)</mo>
      <mfenced open="[" close="]">
          <mfenced open="(" close=")">
              <mi>g</mi>
            <mo>=</mo>
            <munderover>
               <mrow>
                  <mn>1</mn>
               </mrow>
               <mo>(</mo><!--My code failing here-->
                  <mi>text1</mi>
               <mo>)</mo>
               <mrow>
                  <mi>N</mi>
               </mrow>
            </munderover>
         </mfenced>
         <mi>N</mi>
      </mfenced>
      <mfenced open="[" close="]">
         <mfenced open="(" close=")">
            <mfrac>
               <mrow>
                  <mo>(</mo><!--My code failing here-->
                      <mi>text2</mi>
                  <mo>)</mo>
               </mrow>
               <mrow>
                  <mo>2</mo>
               </mrow>
            </mfrac>
         </mfenced>
      </mfenced>
   </math>
</article>

【问题讨论】:

    标签: xml xslt xslt-2.0


    【解决方案1】:

    你在正确的轨道上。我更改了以下内容:

    • copy-of 替换为定向的 apply-templates,这反过来将为所有其他节点选择身份模板
    • 将最后一个模板匹配更改为comment(),因为您想捕获cmets,而不是称为“注释”的元素节点,我想说。不需要//

    您的方法有什么问题?它没有考虑嵌套 mfenced 元素,因为一旦触发了mfenced 的模板匹配,您只需复制其所有内容,包括其中所有潜在的mfenced 元素。

    样式表

    <?xml version="1.0" encoding="UTF-8" ?>
    <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output omit-xml-declaration="yes" indent="yes"/>
    <xsl:strip-space elements="*"/>
    
    <xsl:template match="node() | @*">
        <xsl:copy>
            <xsl:apply-templates select="@* | node()"/>
        </xsl:copy>
    </xsl:template>
    
    <xsl:template match="mfenced">
        <xsl:choose>
            <xsl:when test="descendant::mfrac|descendant::munderover">
                <xsl:copy>
                    <xsl:apply-templates select="@* | node()"/>
                </xsl:copy>
            </xsl:when>
            <xsl:otherwise>
                <mo>
                    <xsl:apply-templates select="@* | node()"/>
                </mo>
            </xsl:otherwise>
        </xsl:choose>
    </xsl:template>
    <xsl:template match="comment()"/>
    </xsl:stylesheet>
    

    输出

    <article>
       <math>
          <mi>P</mi>
          <mo open="(" close=")">
             <mi>g</mi>
          </mo>
          <mfenced open="[" close="]">
             <mfenced open="(" close=")">
                <mi>g</mi>
                <mo>=</mo>
                <munderover>
                   <mrow>
                      <mn>1</mn>
                   </mrow>
                   <mo open="(" close=")">
                      <mrow>
                         <mi>text1</mi>
                      </mrow>
                   </mo>
                   <mrow>
                      <mi>N</mi>
                   </mrow>
                </munderover>
             </mfenced>
             <mi>N</mi>
          </mfenced>
          <mfenced open="[" close="]">
             <mfenced open="(" close=")">
                <mfrac>
                   <mrow>
                      <mo open="(" close=")">
                         <mi>text2</mi>
                      </mo>
                   </mrow>
                   <mrow>
                      <mo>2</mo>
                   </mrow>
                </mfrac>
             </mfenced>
          </mfenced>
       </math>
    </article>
    

    【讨论】:

    • 谢谢先生。工作完美。很好的解释。
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