【发布时间】:2018-08-01 06:04:09
【问题描述】:
我已设法通过 google nodejs API 将视频上传到 YouTube。但是我没有找到一种方法来获取已上传的视频的网址。当我记录我作为响应得到的数据时,它看起来像
{ status: 200,
statusText: 'OK',
headers:
{ 'x-guploader-uploadid': 'AEnB2UqicLz-FhD6KLtuvX_sZYeYQWuXoTM4FFusI6yCSGGlIdxKu3-EIneHhG04CYPqum1Uz8ISVmwIlzZqHrBJ2w-wOmbb6t5hEqOUrPnfRxirEd2tHfM',
etag: '"_gJQceDMxJ8gP-8T2HLXUoURK8c/-WggxUHM10yHZDXznWuNSxlnSYU"',
vary: 'Origin, X-Origin',
'x-goog-correlation-id': 'zaYeqX5ngEo',
'content-type': 'application/json; charset=UTF-8',
'cache-control': 'no-cache, no-store, max-age=0, must-revalidate',
pragma: 'no-cache',
expires: 'Mon, 01 Jan 1990 00:00:00 GMT',
date: 'Wed, 21 Feb 2018 15:19:39 GMT',
'content-length': '975',
server: 'UploadServer',
'alt-svc': 'hq=":443"; ma=2592000; quic=51303431; quic=51303339; quic=51303338; quic=51303337; quic=51303335,quic=":443"; ma=2592000; v="41,39,38,37,35"',
connection: 'close' },
config:
{ adapter: [Function: httpAdapter],
transformRequest: { '0': [Function: transformRequest] },
transformResponse: { '0': [Function: transformResponse] },
timeout: 0,
xsrfCookieName: 'XSRF-TOKEN',
无法看到服务器中的完整日志
上传视频的代码是
var yt = google.youtube('v3');
yt.videos.insert({
part: 'status,snippet',
resource: {
snippet: {
title: "title",
description: "description"
},
status: {
privacyStatus: 'public'
}
},
media: {
body: fs.createReadStream(file)
}
}, function(error, data){
console.log(util.inspect(data, false, null));
console.log(error);
if(error){
} else {
}
});
如何获取上传的视频地址?
【问题讨论】:
-
记录响应并检查。它应该在响应中
-
我已经记录了响应,它显示了一个包含状态:200、状态文本:OK 等的长数据。其中还包含标题、配置和请求对象
标签: node.js google-api youtube-api youtube-data-api google-api-nodejs-client