特定的字符串作为可能的参数 - 枚举？

Question

对于我正在编写的工具，我需要一个“随机文本”生成器。我想让用户能够从这些预制字符串中进行选择：

const string baseCollection = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
const string numbers = "0123456789";
const string specialChars = "°^!\"§$%&/{([)]=}?\\`´*+~'#,;.:-_><|";
const string germanAddition = "ÄÖÜäöü";
const string frenchAddition = "éàèùâêîôûäëïü眫»";
const string russianAddition = " бвгджзклмнпрстфхцчшщйаэыуояеёюиьъ";

应该使用哪些术语来运行此方法。

public string RanText(int length, ???)
{
    string charCollectionString = "";
    foreach(string str in charCollectionStrings) {
        charCollectionString += str;
    }

    //stuff

    return finalString;
}

我曾想过使用枚举，但那些不允许使用字符串。创建一系列可能参数的最简洁方法是什么？

Answer 1

您是否考虑过使用Dictionary<>？例如：

public enum CType
{
    Base,
    Numbers,
    Special,
    German,
    French,
    Russian
}

public readonly Dictionary<CType, string> Collections = new Dictionary<CType, string>
{
    { CType.Base, "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz" },
    { CType.Numbers, "0123456789" },
    { CType.Special, "°^!\"§$%&/{([)]=}?\\`´*+~'#,;.:-_><|" },
    { CType.German, "ÄÖÜäöü" },
    { CType.French, "éàèùâêîôûäëïüçœ" },
    { CType.Russian, "бвгджзклмнпрстфхцчшщйаэыуояеёюиьъ" }
};

public string RanText(int length, CType[] parameters)
{
    string charCollectionString = "";
    foreach (CType param in parameters)
    {
        charCollectionString += Collections[param];
    }
}

然后：

RanText(1, new[] { CType.Base, CType.Numbers, CType.Russian });