找不到页面 (404) 请求方法：GET 请求 URL：http://127.0.0.1:8000/index.html/

Question

我正在尝试创建简单的待办事项列表。我发现了一个小问题。在删除 todo 任务期间，我收到错误（来自主题），但任务实际上正在删除。如何摆脱这个错误？

urls.py

    from django.urls import path, include
    from .views import DeleteTodo
    from . import views
    
    
    app_name = 'todoxd_app'
    
    urlpatterns = [
        path('', views.index, name='index'),
        path('todo/', views.todo, name='todo'),
        path('new_todo/', views.new_todo, name='new_todo'),
        path('delete/<int:pk>/', DeleteTodo.as_view() ,name='delete_todo'),
    ]

delete_todo.html

标题 {% 扩展 'todoxd_app/base.html' %} {% 块内容 %} {% csrf_token %} 您确定要删除此任务吗？ 删除任务 {% endblock 内容 %}

views.py

    from django.shortcuts import render, redirect
    from django.urls import reverse_lazy
    from .models import Task
    from .forms import TaskForm
    from django.views.generic import DeleteView
    
    def index(request):
        return render(request, 'todoxd_app/index.html')
    
    def todo(request):
        objekt = Task.objects.all()
        context = {'objekt': objekt}
        return render(request, 'todoxd_app/todo.html', context)
    
    def new_todo(request):
        if request.method != 'POST':
            form = TaskForm()
        else:
            form = TaskForm(data=request.POST)
            if form.is_valid():
                form.save()
                return redirect('todoxd_app/new_todo')
    
        context = {'form': form}
        return render(request, 'todoxd_app/new_todo.html', context)
    
    class DeleteTodo(DeleteView):
        model = Task
        template_name = 'todoxd_app/delete_todo.html'
        success_url = '/index.html/'

来自 django 项目的网址

    from django.contrib import admin
    from django.urls import path, include
    
    urlpatterns = [
        path('admin/', admin.site.urls),
        path('', include('todoxd_app.urls')),
        path('users/', include('users.urls')),
    ]

如果您发现其他问题，请给我反馈，我只是一个初学者。谢谢！

Answer 1

您需要更新您的success_url。

由于您的应用主页定义为：

path('', views.index, name='index')

您可以编辑为：

success_url = "/"

Answer 2

改变这一行

success_url = '/index.html/'

到

success_url = 'index' # this is the name of the url path in your urls.py

你也可以改变这一行

return redirect('todoxd_app/new_todo')

到

return redirect('new_todo') # again the same thing.... name of the url path in your urls.py file