您的数据模型的结构使某些事情变得不直观,因此如果您在这方面具有灵活性,您可能需要考虑进行更改。
例如,如果您想获取游戏列表并了解谁赢得了游戏,这并非易事,因为游戏表没有获胜球队的列,或者有关如何赢得比赛的信息每支球队进了很多球。相反,你必须加入目标,加入球员,然后加入球员队伍。 (请注意,我无法测试此代码,而且它足够复杂,可能会出现错误。)
from django.db.models import Count, Q, F, Case, When
games = Game.objects.annotate(
team1_goal_count=Count('goals', filter=Q(goals__player__team=F('team1'), distinct=True),
team2_goal_count=Count('goals', filter=Q(goals__player__team=F('team2'), distinct=True),
result=Case(When(Q(team1_goal_count__gt=team2_goal_count), then=F('team1')),
When(Q(team2_goal_count__gt=team1_goal_count), then=F('team2')),
default=None)
)
上面将为您提供一个查询集,其中包含每个团队的目标计数和result 列中获胜团队的 ID(null 在平局的情况下)
如果你想得到一个按胜率排序的球队名单,他们的赢/输/平记录,你必须加入比赛并类似地计算分数(注意,这太复杂了,我不知道如果它甚至像我写的那样工作):
from django.db.models import Subquery, OuterRef
# Use the `games` query from above
scored_games_1 = games.filter(team1_id=OuterRef('pk'))
scored_games_2 = games.filter(team2_id=OuterRef('pk'))
# Need to group by the OuterRef('pk')
scored_games_1 = scored_games_1.values('team1')
scored_games_2 = scored_games_2.values('team2')
# Annotate the counts and select on that column
scored_games_1 = scored_games_1.annotate(count=Count('pk')).values('count')
scored_games_2 = scored_games_2.annotate(count=Count('pk')).values('count')
won_q = Q(result=F('pk'))
lost_q = Q(result__isnull=False) & ~Q(result=F('pk'))
tied_q = Q(result__isnull=True)
teams = Team.objects.annotate(
games_won=Subquery(scored_games_1.filter(won_q)) + Subquery(scored_games_2.filter(won_q)),
games_lost=Subquery(scored_games_1.filter(lost_q)) + Subquery(scored_games_2.filter(lost_q)),
games_tied=Subquery(scored_games_1.filter(tied_q) + Subquery(scored_games_2.filter(tied_q)),
winning_percentage=F('games_won') / (F('games_won') + F('games_lost') + F('games_tied'))
).order_by('-winning_percentage')
在Game 中包含一个列,即获胜团队的 id,这是一种非规范化,使上述所有内容变得如此简单。使Game 和Team 成为多对多关系(即使只能有2 个团队)也会使事情变得更容易。