如何使用 django 请求正确下载文件

Question

我正在运行一个可以上传文件的 Django 应用程序。现在我想使用请求下载文件。我试图创建一个下载文件的视图，这样我就可以用请求进行调用。但它并不完全有效

My model: 

class FileCollection(models.Model):
    name = models.CharField(max_length=120, null=True, blank=True)
    store_file = models.FileField(storage=PrivateMediaStorage(), null=True, blank=True)
    creation_date = models.DateTimeField(null=True, blank=True)

My views



def fileview(request, *args, **kwargs):
    file = FileCollection.objects.first()
    file_path = file.store_file
    print(file_path)
    FilePointer = open(file_path, "r")
    response = HttpResponse(FilePointer, content_type='application/msexcel')
    response['Content-Disposition'] = 'attachment; filename=NameOfFile'

    return response

它告诉我TypeError: expected str, bytes or os.PathLike object, not FieldFile

如果我传入 apiview/admin 中提供的 url，我会得到：FileNotFoundError: [Errno 2] No such file or directory

也试过了：

def fileview(request):
    path = FileCollection.objects.first()
    obj = path.store_file
    o = str(obj)
    file_path = os.path.join(settings.MEDIA_ROOT, o)
    print(file_path)
    if os.path.exists(file_path):
        with open(file_path, 'rb') as fh:
            response = HttpResponse(fh.read(),
                                    content_type="application/vnd.ms-excel")
            response[
                'Content-Disposition'] = 'inline; filename=' + os.path.basename(
                file_path)
            return response

但这给了我ValueError: The view file_storage_api.api.v1.views.fileview didn't return an HttpResponse object. It returned None instead.

这是正确的方法吗？

非常感谢您的帮助或提示。 非常感谢

Answer 1

file_path = file.store_file

不是文件路径，而是 FileField 的一个实例 尝试使用

file_path = file.store_file.name

并使用第二个 sn-p

编辑：这是我使用的代码： l_targetFile 是实际文件的路径

    l_prjPath = os.path.realpath(os.path.dirname(__file__)).replace(<adapt the path here>)
    l_userFileName= <file field>.name.replace('<upload to sub-dir>','')
    l_targetFile = l_prjPath + '/media/' + l_fileObj.file_obj.name
    #return the file
    response = FileResponse(open(l_targetFile, 'rb'),\
                            (l_responseDisposition == 'attachment'))        

    #process the filename as stored on the local machine in case of download
    try:
        #check if it will throw
        l_tmpUserName = l_userFileName.encode('ascii')

        #no error use the non-encoded filename
        l_fileExpr = 'filename="{0}"'.format(l_userFileName)
    except UnicodeEncodeError:
        # Handle a non-ASCII filename
        l_fileExpr = "filename*=utf-8''{}".format(quote(l_userFileName))

    response['Content-Disposition'] = '{0};{1};'.format(l_responseDisposition,l_fileExpr)
    if '.pdf' in l_userFileName:
        response['Content-Type'] = 'application/pdf'
    elif l_dataSource == CMSArchiveEntry.SOURCE_TAG:
        response['Content-Type'] = 'text/html; charset=utf-8'
    return response