【发布时间】:2021-11-05 06:44:05
【问题描述】:
我想将文件从 Google App Engine 上传到 Google Cloud Storage 我正在使用 Pyhton 3.8 和 Flask。
app.yaml:
runtime: python38
requirements.txt
Flask==2.0.0;
google-cloud
google-cloud-storage
我尝试使用 Flask (https://www.tutorialspoint.com/flask/flask_file_uploading.htm) 将文件上传到 /tmp(在 App Engine 临时存储中 (https://cloud.google.com/appengine/docs/standard/python3/using-temp-files))
然后我尝试使用以下代码示例从临时存储上传到 Google Cloud Storage:(https://cloud.google.com/storage/docs/uploading-objects#storage-upload-object-code-sample)
但这给了我这个错误:
OSError: [Errno 30] Read-only file system: 'file.xlsx'
我也尝试过这个示例:(https://github.com/GoogleCloudPlatform/python-docs-samples/blob/master/appengine/standard/storage/api-client/main.py) 并给了我同样的错误。
然后我尝试使用 gsutil (https://cloud.google.com/storage/docs/uploading-objects#gsutil) 使用 subprocess.check_output (Return value of x = os.system(..)) 仍然给我同样的错误。
谁能帮助我?我该怎么办?
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解决了
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谢谢Edo Akse,我的错误是使用“/tmp”而不是“/tmp/”,非常感谢帮助我。
以下是完整的代码。
from flask import Flask, request
from werkzeug.utils import secure_filename
from google.cloud import storage
import os
app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = "/tmp/"
@app.route('/')
def index():
page = '''
<form action="/upload" method="post" enctype="multipart/form-data">
<input name="file" class="custom-file-input" type="file">
<button type="submit" class="btn btn-success">Submit</button>
</form>
'''
return page
@app.route('/upload',methods=["POST"])
def upload():
try:
if request.method == 'POST':
f = request.files['file']
f.save(os.path.join(app.config['UPLOAD_FOLDER'],secure_filename(f.filename)))
#Start Do Main Process Here
TMP_FILE_NAME = os.path.join(app.config['UPLOAD_FOLDER'],secure_filename(f.filename))
BUCKET_NAME = 'fsample123'
result = upload_blob(BUCKET_NAME, TMP_FILE_NAME, f"tmp/{secure_filename(f.filename)}")
#End Do Main Process Here
return result
except Exception as e:
return str(e)
def upload_blob(bucket_name, source_file_name, destination_blob_name):
"""Uploads a file to the bucket."""
# SOURCE:
# https://cloud.google.com/storage/docs/uploading-objects#uploading-an-object
# The ID of your GCS bucket
# bucket_name = "your-bucket-name"
# The path to your file to upload
# source_file_name = "local/path/to/file"
# The ID of your GCS object
# destination_blob_name = "storage-object-name"
storage_client = storage.Client()
bucket = storage_client.bucket(bucket_name)
blob = bucket.blob(destination_blob_name)
blob.upload_from_filename(source_file_name)
return "File {} uploaded to {}.".format(source_file_name, destination_blob_name)
if __name__ == '__main__':
app.run()
【问题讨论】:
-
我认为您的问题可能不在于 GCS 库,而在于存储临时文件的位置。您没有指定 GAE Flex 或 Standard,但两者都处理临时文件存储。例如,请参阅this doc 以了解标准
-
刚刚注意到您处理的是 GAE 标准,所以上面的链接适用...
-
是的,我使用的是 GAE 标准,那么我应该怎么做才能从 GAE 上传到 GCS?如果问题是临时文件存储,我应该将我的文件临时上传到 GCS 哪里?
标签: python flask google-app-engine google-cloud-storage