【发布时间】：2015-08-12 11:19:48
【问题描述】：
在过去的两个月里，我一直在断断续续地处理这个问题，尽管我看了很多次，但我无法让它发挥作用。 此脚本检查用户定义变量的每日日志文件，因此他们不必手动查看每一个。检查当前月份效果很好，但是如果用户想检查 20 天，而今天是本月的 12 日，我希望能够返回到上个月（而不是查找带有日期 20150399 等）。我已经检查了我的日期/日期计算的逻辑，它们似乎没问题（如果在 BASH 中有更好的方法来做到这一点，我愿意接受建议）。当我尝试调试时会发生意外的文件结尾。我对编写包含超过 20 行左右的脚本有点陌生，但我就是想不出我所缺少的东西。 我尝试了各种修复，但无济于事，但我认为这是最后一次迭代。 想法？
#!/bin/bash
########################################################
# multi_log_chk.sh
# This script will take input from the user and report which
# CyberFusion MFT logs contain what the user is looking for.
# Hopefully this will save the user having to search through every
# stinking log file to find what they are looking for.
# 20150406 pxg007 started typing
# 20150413 pxg007 added && comparison for back out (line 28)
# added message for no entries found (line 32, 38, 48-52)
# Added some further description (line 16)
# 20150424 pxg007 Added logic to calculate previous month and if necessary, year. (Lines 16-24, 60-78 )
#
########################################################
currDate=`date +%d%B%C%y`
currDay=`date +%d`
currMnth=`date +%m`
currYear=`date +%C%y`
case $currMnth in #Let's establish number of days for previous month
05 | 07 | 10 | 12 ) lastMnthD=30;;
01 |02 | 04 | 06 | 09 | 08 | 11 ) lastMnthD=31;;
03 ) lastMnthD=28;; ##and screw leap year
esac
if [ $currMnth -eq 01 ]; then ##accounting for January
lastMnth=12
else
lastMnth=$((currMnth-1))
fi
if [ $lastMnth -eq 12 ]; then ## accounting for Dec of previous year
lastMnthYr=$((currYear-1))
else
lastMnthYr=$currYear
fi
echo "This script will find entries for your query in whatever available MFT logs you request."
echo " "
echo "For instance - how many log files have transfer entries with \"DOG\" in them?"
echo " "
echo "I also will also give an estimate of how many transfers per log file contain your query, give or take a couple."
echo " "
echo "This search is case sensitive, so \"DOG\" is *** NOT *** the same as \"dog\""
echo " "
read -p "What text you are looking for? Punctuation is okay, but no spaces please. " looking ### what we want to find
echo " "
echo "Today's date is: $currDate."
echo " "
read -p "How many days back do you want to search(up to 25)? " daysBack ### How far back we are going to look
if [ "$daysBack" == 0 ] && [ "$daysBack" >> 25 ]; then
echo "I said up to 25 days. We ain't got more than that!"
exit 1
fi
echo " "
echo "I am going to search through the last $daysBack days of log files for:\"$looking\" "
echo " "
read -p "Does this look right? Press N to quit, or any other key to continue: " affirm
if [ "$affirm" = N ] && [ "$affirm" = n ]; then ###Yes, anything other than "N" or "n" is a go
echo "Quitter!"
exit 1
else
nada=0 ### Used to test for finding anything
backDate=$((currDay-daysBack)) ### current month iterator (assuming query covers only current month)
if (("$daysBack" => "$currDay")); then ## If there are more logs requested than days in the month...
lastMnthCnt=$((daysBack-currDay)) ### how many days to check last month
lastMnthStrt=$((lastMnthD-lastMnthCnt)) ## last month start and iterator
backDate=$(currDay-(daysBack-lastMnthCnt)) # Setting the iterator if we have to go back a month
while (("$lastMnthStrt" <= "$lastMnthD" )); do
foundIt=$(grep "$looking" /CyberFusion/log/Log.txt."$lastMnthYr$lastMnth$lastMnthStrt" | parsecflog | wc -l )
howMany=$((foundIt/40+1)) ### Add one in case there are less than 40 lines in the record.
if (("$foundIt" > 0))
then
nada=$((nada+1))
echo "Log.txt.$lastMnthYr$lastMnth$lastMnthStrt contains $looking in approximately $howMany transfer records."
lastMnthStrt=$((lastMnthStrt+1))
echo " "
else
lastMnthStrt=$((lastMnthStrt+1))
fi
fi
backDate=$((currDay-daysBack)) ### current month iterator (assuming query covers only current month)
while (("$backDate" <= "$currDay")); do
foundIt=$(grep "$looking" /CyberFusion/log/Log.txt."$backDate" | parsecflog | wc -l )
howMany=$((foundIt/40+1)) ### Add one in case there are less than 40 lines in the record.
if (("$foundIt" > 0))
then
nada=$((nada+1))
echo "Log.txt.$backDate contains $looking in approximately $howMany transfer records."
backDate=$((backDate+1))
echo " "
else
backDate=$((backDate+1))
fi
if [ "$nada" \< 1 ]
then
echo " "
echo "I found no entries for $looking in any log file."
fi
【问题讨论】：
-
你试过
date --date="-20 days" +"%d%B%C%y"吗？ -
第一行
echo下的内容与这里的问题有关吗？因为如果不是，您应该将其从帖子中删除。 -
我认为是。我很确定问题出在 if 或 while 语句之一中。我粘贴了整个内容，只是为了更好地了解我对整个混乱的处理方式。
-
将您的脚本粘贴到shellcheck.net。有几个语法错误。
-
谢谢 rojomke！我知道一定有什么地方可以比 BASH -x 更好地评估我的代码。这正是我所需要的。