有什么方法可以循环 a-z 而不是编写多个 for 循环语句？

Question

所以我试图对给定列表进行字符计数。

a = ["farshad", "ghassemi?d", "madam", "?radar?", "duration", "con?tained"]

我的预期输出是：

farshad 包含 2 个 a

这样下去.....

我的代码是：

def charCount():
    a = ["farshad", "ghassemi?d", "madam", "?radar?", "duration", "con?tained"]

    for word in a:
        for letter in word:
            x = word.count("a")
        print(word, "contains", x, "a")

    for word in a:
        for letter in word:
            x = word.count("d")
        print(word, "contains", x, "d")

charCount()

我试图在一个 for 循环中完成这一切，例如 A-Z ....

感谢您的帮助：D

Answer 1

您可以在 2 个 for 循环中执行此操作。 （我假设这个问题意味着 1 个单独的 for 循环并允许嵌套 for 循环）我就是这样做的：

import string

def charCount():
    a = ["farshad", "ghassemi?d", "madam", "?radar?", "duration", "con?tained"]

    for word in a:
        for i in string.ascii_lowercase:
            x = word.lower().count(i)
            print(word, "contains", x, i)

charCount()

您需要做的就是遍历每个字符。 string.ascii_lowercase 包含每个小写字母，所以我使用了它。然后，我们得到 word.lower() 中 i 的计数。 word.lower() 将单词转换为小写，使其也可用于大写。

如果你想进一步缩短它，你可以像这样改变内部 for 循环：

def charCount():
    a = ["farshad", "ghassemi?d", "madam", "?radar?", "duration", "con?tained"]

    for word in a:
        for i in string.ascii_lowercase: print(word, "contains", word.lower().count(i), i)

Answer 2

您是否要检查每个单词的整个字母表？还是只是那些词中的字母？

如果您只想计算每个单词中的字母，可以尝试：

def charCount():

    a = ["farshad", "ghassemi?d", "madam", "?radar?", "duration", "con?tained"]

    for word in a:

        word_set = set(word)

        for letter in word_set:
            x = word.count(letter)
            print(word, "contains", x, letter)

这将为每个单词创建一个set，这将防止打印重复的字母。

如果您想忽略这些问号，可以将其放在内部循环中：

            if letter == '?':
                continue

请记住，此解决方案不会以任何特定顺序对您的字母进行排序，因为集合本身就是无序的。

Answer 3

我的回答

def charCount(search_letter):
    a = ["farshad", "ghassemi?d", "madam", "?radar?", "duration", "con?tained"]
    for word in a:
        word = word.lower()
        for letter in word:
            x = word.count(search_letter)
            print(word, "contains", x, search_letter)
# letters = ("aeiou")
letters = ("abcdefghijklmnopqrstuvwxyz")    
for search_letter in letters:
    charCount(search_letter)