php函数中的foreach循环

Question

我正在尝试创建一个贯穿 Db 表的 foreach 循环，并将其在函数中回显，但是当我尝试执行此操作时，它会获取对象中的行，并回显对象与我有多少行一样多次，并且不会继续到表中的下一个对象。帮助表示赞赏。这是我的代码：

function hotels_from_db() {
include 'DbConnection.php';
$sql = "select * from hotels";

$result = $mysqli->query($sql);

$row = $result->fetch_object();

    foreach ($row as $value) {   
    $foundhotel = "<h1>" . $row->hotel_name . "</h1></br>";
    $foundhotel.= $row->hotel_adress . "</br>";
    $foundhotel.= $row->hotel_postal_code . "</br>";
    $foundhotel.= $row->description;
    echo "$foundhotel";
    }  
  }

---

也尝试过这样做，但这只会显示表格中的最后一家酒店。

function hotels_from_db() {
include 'DbConnection.php';
$sql = "select * from hotels";

$result = $mysqli->query($sql);

$row = $result->fetch_object();
while($row = $result->fetch_object()){           
    $foundhotel = "<h1>" . $row->hotel_name . "</h1></br>";
    $foundhotel.= $row->hotel_adress . "</br>";
    $foundhotel.= $row->hotel_postal_code . "</br>";
    $foundhotel.= $row->description;
    echo "$foundhotel";
    }  

}

Answer 1

fetch_object 需要为每一行提取调用。 请尝试以下操作：

function hotels_from_db() {
    include 'DbConnection.php';
    $sql = "select * from hotels";

    if ($result = $mysqli->query($sql)) {

        /* fetch object array */
        while ($obj = $result->fetch_object()) {
            $foundhotel = "<h1>" . $obj->hotel_name . "</h1></br>";
            $foundhotel.= $obj->hotel_adress . "</br>";
            $foundhotel.= $obj->hotel_postal_code . "</br>";
            $foundhotel.= $obj->description;
            echo "$foundhotel";        
        }

        /* free result set */
        $result->close();
    }
}

Answer 2

$row = $result->fetch_all(MYSQLI_ASSOC); // MAKE ARRAY ASSOCIATIVE ARRAY

foreach ($row as $value) {   
    $foundhotel = "<h1>" . $value->hotel_name . "</h1></br>";
    $foundhotel.= $value->hotel_adress . "</br>";
    $foundhotel.= $value->hotel_postal_code . "</br>";
    $foundhotel.= $value->description;
    echo "$foundhotel";
}  

}

Answer 3

->fetch_object 只检索一行

试试这个：

function hotels_from_db() {
include 'DbConnection.php';
$sql = "select * from hotels";
$result = $mysqli->query($sql);

while($row = $result->fetch_object()) {   
    $foundhotel = "<h1>" . $row->hotel_name . "</h1></br>";
    $foundhotel.= $row->hotel_adress . "</br>";
    $foundhotel.= $row->hotel_postal_code . "</br>";
    $foundhotel.= $row->description;
    echo "$foundhotel";
}  

}

Answer 4

应该是：

function hotels_from_db() {
    include 'DbConnection.php';
    $sql = "select * from hotels";

    $result = $mysqli->query($sql);

    $row = $result->fetch_all();

    foreach ($row as $value) {   
        $foundhotel = "<h1>" . $value->hotel_name . "</h1></br>";
        $foundhotel.= $value->hotel_adress . "</br>";
        $foundhotel.= $value->hotel_postal_code . "</br>";
        $foundhotel.= $value->description;
        echo "$foundhotel";
    }  
}