防止 foreach 循环重复 -laravel

Question

我通过代码从我们的数据库中获取服务

'services' =>  Service::with('seller.user', 'seller.level', 'subcategory')
            ->whereHas('seller', function ($query) {
                return   $query->where('status', 'active');
            })
            ->Where('tags', 'like', '%' . $this->tag . '%')
            ->withAvg('review', 'rating')
            ->withCount('review')
            ->paginate(20)

如何忽略循环中重复的子类别

 @foreach ($services as $service)
        $$service->subcategory->name
        @endforeach

我得到了很多重复的子类别

我需要子类别的详细信息而不仅仅是名称

关系

class Service extends Model
{
    public function subcategory()
    {
        return $this->belongsTo(Subcategory::class);
    }
}

class Subcategory extends Model
{
    public function service()
    {
        return $this->hasMany(Service::class);
    }
}

餐桌服务

Schema::create('services', function (Blueprint $table) {
        $table->id();
        $table->foreignId('seller_id')->constrained()->onDelete('cascade')->onUpdate('cascade');
        $table->foreignId('subcategory_id')->constrained()->onDelete('cascade')->onUpdate('cascade');
        $table->string('title')->nullable();
        $table->string('slug')->nullable();
        $table->float('price')->nullable();
        $table->json('tags')->nullable();
    }

表格子类别

  Schema::create('subcategories', function (Blueprint $table) {
        $table->id();
        $table->foreignId('category_id')->constrained()->onDelete('cascade')->onUpdate('cascade');
        $table->string('name');
    }

Answer 1

仅获取唯一 ID 或唯一名称。可能与您的数据库不同。

'services' =>  Service::with('seller.user', 'seller.level',
 'subcategory' => function($query) {
          $query->get()->unique('name')
      })
       ->whereHas('seller', function ($query) {
            return   $query->where('status', 'active');
        })
        ->Where('tags', 'like', '%' . $this->tag . '%')
        ->withAvg('review', 'rating')
        ->withCount('review')
        ->paginate(20);

也可以使用以下方法

1. ->distinct('name')->get();

2. ->distinct()->get(['name']);

更多请查看Aggregating Related Models

Answer 2

您可以尝试以下方法：

@php
$subcategories = array();
foreach ($services as $key => $service) {
    array_push($subcategories, $service->subcategory->name);
}
$subcategories = array_unique($subcategories);
@endphp
@foreach ($subcategories as $key => $subcategory)
    {{ $subcategory }}
@endforeach