【发布时间】:2021-06-11 08:19:11
【问题描述】:
我被这个聪明的问题困住了。我找不到可定制的解决方案。
我正在尝试使用foreach 打印我的List of Lists。这是代码:
int i = 0;
StringBuilder sb = new StringBuilder();
foreach (var subList in result)
{
i++;
Console.WriteLine(sb.Append("******\n").Append("Group ").Append(i).Append(" - ").
Append("Number of students: ").Append(subList.Count()).Append("\n").Append("
Name:").Append("\n"));
var exp = subList.GetEnumerator();
while (exp.MoveNext())
{
Console.WriteLine(sb.Append(" ").Append(exp.Current.ToString()).Append("\n"));
}
}
我正在尝试得到这个结果(例如):
Group 1 - Number of students: 3
Name:
this
is
a
Group 2 - Number of students: 3
Name:
test
again
and-again
等等。
问题是我总是得到这个(它每次都来自foreach):
Console.WriteLine(sb.Append("******\n").Append("Group ").Append(i).Append(" - ").
Append("Number of students: ").Append(subList.Count()).Append("\n").Append("
Name:").Append("\n"));
像这样:
******
Group 1 - Number of students: 3
Name:
******
Group 1 - Number of students: 3
Name:
this
******
Group 1 - Number of students: 3
Name:
this
is
******
Group 1 - Number of students: 3
Name:
this
is
a
列表的其余部分以此类推。谁能指导我解决这个问题。 非常感谢任何帮助。
【问题讨论】:
-
您还没有向我们展示
result的外观,因此很难对您的代码形成意见。