相邻打印 2 个 for 循环

Question

我想知道如何将 2 个 for 循环并排打印出来？

这些是循环：

for(vector<Student>::iterator it = studenti.begin(); it != studenti.end(); ++it)
        cout << "| " << it->brojIndeksa << "          " << it->ime << "  " << it->prezime;
for(map<string,string>::iterator it = ocjene.begin(); it!= ocjene.end(); ++it)
        cout << "     " << it->first << " - " << it->second << endl;

我想要的输出：

| brojIndeksa ime prezime first - second

| brojIndeksa ime prezime first - second

| brojIndeksa ime prezime first - second

我的输出：

| brojIndeksa          ime  prezime| brojIndeksa          ime  prezime     first - second
     first - second

编辑：

struct Predmet {
    string naziv;
    string odsjek;
    istream& dodaj_predmet(istream &);
    void sort_predmeti();
};

struct Student {
    string brojIndeksa;
    string ime;
    string prezime;
    map<std::string, string> ocjene;
    istream& dodaj_studenta(istream &);
    void sort_studenti();
};

map<std::string, string> ocjene 包含 2 个输入字符串，第一个必须是来自 Predmet 结构的 naziv。

新输出：

| 1808 John Doe EJ 10

| PIM 10

| 1809 Jessica Doe PIM 10

Answer 1

您可以在同一个循环中使用两个迭代器进行迭代：

auto studenti_it = studenti.begin();
auto ocjene_it = ocjene.begin();

for (; studenti_it != studenti.end() && ocjene_it != ocjene.end(); ++studenti_it, ++ocjene_it)
{
    // Print using both iterators...
}

---

在您进行编辑后，我们看到地图是 Student 结构的成员，我猜测您想要的是首先迭代 @ 987654324@ 向量，然后在其中有一个Student::ocjene 映射的循环？

然后你会有类似的东西

// First iterate over the vector
for (auto const& student : studenti)
{
    std::cout << "| " << student.brojIndeksa << "          " << student.ime << "  " << student.prezime << '\n';

    
    // Then inside iterate over the map
    for (auto const& oj : student.ocjene)
    {
        std::cout << '\t' << oj.first << ' ' << oj.second << '\n';
    }
}