为什么我的代码不接受字母作为用户输入

Question

我的代码运行时没有错误或任何东西，但在我输入“F”或“P”后，它会跳到“单击任何按钮继续”，但如果我使用任何数字，它会通过代码正常运行。

这是我的代码：

#include <iostream>
#include <iomanip> // needed to use set precision

using namespace std;

void calcCost(double f_benefits, double F, double total_cost, double emp_salary)
{
    if (f_benefits == F)
        (total_cost += emp_salary * 1.5);
    else 
        (total_cost += emp_salary * 1.25);   // calculating operating function

}

int main()
{
    
    double num_emp = 0; // employees
    double emp_salary = 0; // employees salary
    double f_benefits = 0; // are they full time or part time benifits
    double total_cost = 0;
    int F = 0;
    int P = 0;

    cout << setw(69) << "Cost of Operation\n\n";

    cout << "Please enter the number of employees to process: ";
    cin >> num_emp;
    cout << endl;

    for (int i = 1; i <= num_emp; i++)  // loop for each employees salary and benifits
    {
        cout << "Please enter the salary for employee " << i << ":";
        cin >> emp_salary;
            
        cout << "Is employee " << i << " receiving(F)ull or (P)artial benefits ? Please enter F or P : "; // Dont forget input validation for this step
        cin >> f_benefits;
        
    }

        return 0;
}

Answer 1

f_benefits 不应该是字符串吗？

Answer 2

“cin >> f_benefits”正在尝试读取双精度值。您应该将响应读入字符或字符串。读入字符串需要在返回之前换行。

你还应该检查你得到的是“F”还是“P”。