当前获取 django-mptt 的绝对 URL 的方法是什么？

Question

我阅读了其他问题，但我没有发现任何对 Django 3 有用的东西，它们只是不起作用。

需要这样的链接类型：post/categories/subcategories/**etc

我认为一个适当的答案对每个人都有用。

告诉我如何为 DetailView 做这件事

class Category(MPTTModel):
title = models.CharField(max_length=255, verbose_name=_('Заголовок'))
slug = models.SlugField(max_length=255, verbose_name=_('URL'), blank=True)
parent = TreeForeignKey('self', null=True, blank=True, related_name='children', db_index=True, on_delete=models.CASCADE)

class MPTTMeta:
    order_insertion_by = ['title']

class Meta:
    unique_together = ['parent', 'slug']
    verbose_name = _('Категория')
    verbose_name_plural = _('Категории')

urls.py

urlpatterns = [
path('category/<slug:slug>/', CategoryListView.as_view(), name='category_detail'),
]

views.py

class CategoryListView(ListView):
model = Category
template_name = 'modules/post/category_detail.html'
context_object_name = 'category'
queryset = Category.objects.all()

def get_queryset(self):
    queryset = self.queryset.filter(slug=self.kwargs['slug'])
    return queryset

Answer 1

你可以reverse urls。

代码库/urls.py

urlpatterns = [
    path('', include('my_app.urls', namespace='my_app_namespace')),
]

代码库/my_app/urls.py

urlpatterns = [
    path('category/<int:my_var>', views.my_view, name='my_view_name'),
]

代码库/any_python_file.py

from django.urls import reverse
reverse('my_app_namespace:my_view_name', args=[my_var])
>>> 'https://...'