【发布时间】:2019-08-14 08:30:33
【问题描述】:
我正在尝试在 docker 容器中启动一个简单的 Flask“Hello world”应用程序,但我不断收到此错误:“OSError: [Errno 8] Exec format error: '/app/app.py'”
我的主机操作系统是 Windows 10。
我的 Dockerfile:
FROM python:3.6
ENV PYTHONBUFFERED 1
ADD . /app
WORKDIR /app
RUN pip install -r requirements.txt
我有 Flask==1.0.2 的 requirements.txt。
app.py:
from flask import Flask
app = Flask(__name__)
@app.route("/")
def hello():
return "Hello World!"
if __name__ == '__main__':
app.run(host='0.0.0.0', port=8000, debug=True)
和 docker-compose.yml:
version: '3'
services:
app:
build: .
command: python app.py
ports:
- "8000:8000"
容器的整个日志:
app_1 | * Serving Flask app "app" (lazy loading)
app_1 | * Environment: production
app_1 | WARNING: Do not use the development server in a production environment.
app_1 | Use a production WSGI server instead.
app_1 | * Debug mode: on
app_1 | * Running on http://0.0.0.0:8000/ (Press CTRL+C to quit)
app_1 | * Restarting with stat
app_1 | Traceback (most recent call last):
app_1 | File "app.py", line 9, in <module>
app_1 | app.run(host='0.0.0.0', port=8000, debug=True)
app_1 | File "/usr/local/lib/python3.6/site-packages/flask/app.py", line 943, in run
app_1 | run_simple(host, port, self, **options)
app_1 | File "/usr/local/lib/python3.6/site-packages/werkzeug/serving.py", line 988, in run_simple
app_1 | run_with_reloader(inner, extra_files, reloader_interval, reloader_type)
app_1 | File "/usr/local/lib/python3.6/site-packages/werkzeug/_reloader.py", line 332, in run_with_reloader
app_1 | sys.exit(reloader.restart_with_reloader())
app_1 | File "/usr/local/lib/python3.6/site-packages/werkzeug/_reloader.py", line 176, in restart_with_reloader
app_1 | exit_code = subprocess.call(args, env=new_environ, close_fds=False)
app_1 | File "/usr/local/lib/python3.6/subprocess.py", line 287, in call
app_1 | with Popen(*popenargs, **kwargs) as p:
app_1 | File "/usr/local/lib/python3.6/subprocess.py", line 729, in __init__
app_1 | restore_signals, start_new_session)
app_1 | File "/usr/local/lib/python3.6/subprocess.py", line 1364, in _execute_child
app_1 | raise child_exception_type(errno_num, err_msg, err_filename)
app_1 | OSError: [Errno 8] Exec format error: '/app/app.py'
flaskdockerproject_app_1 exited with code 1
更新
在我在 app.py 中添加 shebang 之后,就像@larsks 说的那样,我收到了这个错误: "FileNotFoundError: [Errno 2] 没有这样的文件或目录:'/app/app.py': '/app/app.py'。
所有文件都在容器中并且在正确的位置。
【问题讨论】:
-
如果将适当的 shebang 行添加到 Python 脚本(例如
#!/usr/local/bin/python3)会发生什么? -
@larsks 我用不同的 shebang "#!/usr/bin/env python" 尝试过,但得到了这个错误:"/usr/bin/env: 'python3\r': No such file或目录”。但是现在当我添加你的 shebang 时,它实际上是在说“FileNotFoundError: [Errno 2] No such file or directory: '/app/app.py': '/app/app.py'”