在引发表单错误时调试为假时，如何使 Django 表单方法不为 500？

Question

我的登录代码如下：

class LoginForm(forms.Form):
    email = forms.EmailField(max_length = 254, min_length = 6)
    password = forms.CharField(min_length = 8, widget = forms.PasswordInput())

    def Login(self):
        email = self.cleaned_data.get('email')
        password = self.cleaned_data.get('password')
        user = authenticate(email = email, password = password)

        if (user is None) or (user is not None and user.is_active is False):
            raise forms.ValidationError('Login is incorrect.')

        return user

但是，当我在我的站点上将调试设置为 false 时，只要登录不正确，我就会收到 500 错误，而不是显示 ValidationError 的表单。我这样称呼它：

if form.is_valid():
    user = form.Login()

那是在视图方法中。我在这里想念什么？如何正确调用此表单错误，使其在调试设置为 false 时不会出现 500？

Answer 1

这样打电话

def clean(self):
    password = self.cleaned_data.get('password')
    email = self.cleaned_data.get('email')   
    user = authenticate(email = email, password = password)
    if (user is None) or (user is not None and user.is_active is False):
        raise forms.ValidationError('Login is incorrect.')
    return self.cleaned_data

def login(self,request):
    user = authenticate(email = self.cleaned_data.get('email'),password = self.cleaned_data.get('password'))
    user = authenticate(username=username, password=password)
    return user