我可以告诉外部函数从其本地函数内部返回吗？

Question

我有一个 IEnumerator，我需要在函数内部进行一些检查，如果其中一些检查失败，我需要进行一些维护，然后退出 IEnumerator。但是当我将yield break 写入内部函数时，它认为我正在尝试从该内部函数返回。

我想我可以在内部函数调用之后写yield break，但我想保持 DRY。

private IEnumerator OuterFunction()
{
    //bla bla some code

    //some check:
    if (!conditionA)
        Fail();

    //if didn't fail, continue normal code

    //another check:
    if (!conditionB)
        Fail();

    //etc....

    //and here's the local function:
    void Fail()
    {
        //some maintenance stuff I need to do

        //and after the maintenance, exit out of the IEnumerator:
        yield break;
        //^ I want to exit out of the outer function on this line
        //but the compiler thinks I'm (incorrectly) returning from the inner function Fail()
    }
}

Answer 1

您需要在 OuterFunction() 中放置 yield break。见What does "yield break;" do in C#?

private IEnumerator OuterFunction()
{
    //bla bla some code

//some check:
if (!conditionA){
    Fail();
    yield break;
}

//if didn't fail, continue normal code

//another check:
if (!conditionB){
    Fail();
    yield break;
}

//etc....

//and here's the local function:
void Fail()
{
    //some maintenance stuff I need to do

    //and after the maintenance, exit out of the IEnumerator:

    //^ I want to exit out of the outer function on this line
    //but the compiler thinks I'm (incorrectly) returning from the inner function Fail()
}
}