【发布时间】：2016-03-22 04:50:13
【问题描述】：
我已经有一个使用 PostgreSQL 作为数据库的应用程序。我想使用 Django 构建服务。试过“inspectdb”......但它给出了一个期望：
Traceback (most recent call last):
File "manage.py", line 10, in <module>
execute_from_command_line(sys.argv)
File "/usr/local/lib/python3.4/dist-packages/django/core/management/__init__.py", line 350, in execute_from_command_line
utility.execute()
File "/usr/local/lib/python3.4/dist-packages/django/core/management/__init__.py", line 342, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
File "/usr/local/lib/python3.4/dist-packages/django/core/management/base.py", line 348, in run_from_argv
self.execute(*args, **cmd_options)
File "/usr/local/lib/python3.4/dist-packages/django/core/management/base.py", line 399, in execute
output = self.handle(*args, **options)
File "/usr/local/lib/python3.4/dist-packages/django/core/management/commands/inspectdb.py", line 25, in handle
for line in self.handle_inspection(options):
File "/usr/local/lib/python3.4/dist-packages/django/core/management/commands/inspectdb.py", line 70, in handle_inspection
constraints = connection.introspection.get_constraints(cursor, table_name)
File "/usr/local/lib/python3.4/dist-packages/django/db/backends/postgresql/introspection.py", line 172, in get_constraints
"foreign_key": tuple(used_cols[0].split(".", 1)) if kind.lower() == "foreign key" else None,
IndexError: list index out of range
【问题讨论】：
-
嗯，它是一个非常大的数据库吗？你能自己编写模型吗？
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嗨，克里斯，有很多关系。认为这很容易出错
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我听到了，但我不会依赖这样的捷径。反正一定会出错——相信你遇到过一个哈哈。我会自己编写模型，并编写一个数据库迁移脚本，将数据库中的内容以相当大的块复制到 django 中。这很乏味，但我不知道你还能怎么做。
标签： python django postgresql psycopg2