如何将图像上传到文件夹并将其路径传递给 django 中的视图函数？

Question

我想使用 django 模板中的输入文件标签上传图像文件。然后我想做两件事： 1）首先我想将上传的图像存储在我项目的目录中。我想在我的应用程序的静态目录下的 img 目录中上传文件，以便轻松访问它。 2）其次，我想将这个新存储的图像的文件名发送到一个名为detect_im()的视图函数

模板：

<form style="display:inline-block;">
      <input type="file" class="form-control-file">
      <input type="submit" value="Upload"=>
</form>

views.py 中的视图函数

def detect_im(request):
    haar_file = 'C:\\Users\\Aayush\\ev_manage\\face_detector\\haarcascade_frontalface_default.xml'
    datasets = 'datasets\\'
    myid = random.randint(1111, 9999)

    path = "C:\\Users\\Aayush\\ev_manage\\face_detector\\" + datasets + str(myid)
    if not os.path.isdir(path):
        os.mkdir(path)

    (width, height) = (130, 100)
    face_cascade = cv2.CascadeClassifier(haar_file)


    filename = ""  //I WANT THE STORED FILE NAME VALUE HERE TO COMPLETE THE PATH FOR FURTHER DETECTION PROCESS BY OPENCV.


    image_path = "C:\\Users\\Aayush\\ev_manage\\face_detector\\static\\img\\" + filename

    count = 1
    while count < 30:
        im = cv2.imread(image_path)
        gray = cv2.cvtColor(im, cv2.COLOR_BGR2GRAY)
        faces = face_cascade.detectMultiScale(gray, 1.3, 4)
        for (x, y, w, h) in faces:
            cv2.rectangle(im, (x, y), (x + w, y + h), (255, 0, 0), 2)
            face = gray[y:y + h, x:x + w]
            face_resize = cv2.resize(face, (width, height))
            cv2.imwrite('% s/% s.png' % (path, count), face_resize)
        count += 1

        key = cv2.waitKey(10)
        if key == 27:
            break

    return render(request, 'add_dataset.html', {'uid': myid})

最终的流程应该是这样，用户添加图像并单击上传，然后图像被上传到目录，并使用文件名调用 detect_im() 函数，并且该文件名用于 opencv 的路径变量以检测面对它。

感谢阅读。请发布一个至少添加一些代码的答案，因为我是 python 的新手。

Answer 1

使用来自 django 模板的输入文件标签上传图像文件，然后 将上传的图片存储在我项目的目录中

尝试使用枕头：

首先，安装包

pip3 install Pillow

接下来，创建一个字段和函数

在你的 models.py 中：

# models.py 
import os

from django.db import models
from django.utils.timezone import now as timezone_now
from django.utils.translation import ugettext_lazy as _


def upload_to(instance, filename):
    now = timezone_now()
    base, ext = os.path.splitext(filename)
    ext = ext.lower()
    return f"(your_dir)/{now:%Y/%m/%Y%m%d%H%M%S}{ext}"
    # Do add the date as it prevents the same file name from occuring twice
    # the ext is reserved for the file type and don't remove it


class MyExampleClass(models.Model):
    ...
    picture = models.ImageField(_("Picture"), upload_to=upload_to, blank=True, null=True)

然后，创建一个表单来上传图片：

# forms.py 
from django import forms


class MyExampleForm(forms.ModelForm):
    class Meta:
        model = MyExampleClass
        fields = ["picture"]

记得在视图和你的 url 中渲染它：

# views.py 
from django.shortcuts import render, redirect

from .forms import MyExampleForm


def add_image(request):
    form = MyExampleForm()
    if request.method == "POST":
        form = MyExampleForm(data=request.POST, files=request.FILES)
    if form.is_valid():
        form.save()
        return redirect("")
    else:
        return render(request, "myexamplehtml.html", {"form": form})

# quotes/urls.py
from django.urls import path

from .views import MyExampleView

urlpatterns = [
    path('foobar/', add_image, name='myexampleview'),
]

最后，将其添加到您的 HTML 文件中：

{% block content %}
    <form method="post" action="your_url" enctype="multipart/form-data">
        {% csrf_token %}
        {{ form.as_p }}
        <button type="submit">submit</button>
    </form>
{% endblock %}

关于第二部分，我认为您可以像这样访问用户的变量：

MyExampleModel._meta.get_field('picture')

然后把这段代码放到任何你想要它运行的地方

希望这行得通！

Answer 2

你可以按照这个来获取上传文件的路径...

#myImage is your Model
#image is your Model field

myImage.save()
got_url = Image.image.url

print(got_url)

回答链接：I am wondering how can we get path of uploaded Image (imageUrl) in views.py file in Django