【发布时间】:2020-09-29 18:30:41
【问题描述】:
如何在通用FormView 内从def form_valid(self): 重定向到另一个页面。
我知道我应该做类似Super(className, self).form_valid(form): 的事情,但这永远不会重定向到动态链接,而只会转到success URL
这是我的代码:
class ProductCreateView(FormView):
form_class = ProductCreateForm
template_name = 'back_office/product_create_form.html'
success_url = reverse_lazy('product_recipe_wrapper')
def form_valid(self, form):
category = Category.objects.get(id=self.kwargs['pk'])
name = form.cleaned_data['name']
image = form.cleaned_data['image']
big_size = form.cleaned_data['big_size']
mid_size = form.cleaned_data['mid_size']
small_size = form.cleaned_data['small_size']
new_product = Product.objects.create(category=category, name=name, image=image)
big_size_object = ProductSize.objects.create(product=new_product, size=Size.objects.get(id=1),
sell_price=big_size)
mid_size_object = ProductSize.objects.create(product=new_product, size=Size.objects.get(id=2),
sell_price=mid_size)
small_size_object = ProductSize.objects.create(product=new_product, size=Size.objects.get(id=3),
sell_price=small_size)
if small_size_object.sell_price != 0:
return reverse_lazy('product_small_recipe', args=[small_size_object.id])
def get_context_data(self, *args, **kwargs):
context = super(ProductCreateView, self).get_context_data()
context['category'] = Category.objects.get(id=self.kwargs['pk'])
return context
【问题讨论】:
-
如果您返回
super().form_valid(form),那么您可以覆盖get_success_url方法而不是success_url并动态更改URL。但是在这种情况下,您使用的是small_size_object.id,因此在form_valid方法中返回重定向可能更清晰。
标签: python django django-forms django-views django-generic-views