【问题标题】:simple django class-based generic views: am I doing it right?简单的基于 django 类的通用视图:我做得对吗?
【发布时间】:2026-01-31 05:10:01
【问题描述】:

我正在 django 中开发一个简单的“待办事项”应用程序(两种模型:List 和 Item)。尝试学习和使用基于类的通用视图。我有以下三个显示视图工作,但我请求快速代码审查,看看在我继续创建、更新和删除之前,我是否可以做些什么来改进我对 django 的 ListView 和 DetailView 的使用/理解。提前感谢您的任何建议。

# class-based generic views for my lists, a list's items, and item detail...
class MyListsView(ListView):
    """Display My Lists"""
    template_name = 'cmv_app/my_lists.html'
    context_object_name = 'my_lists'

    def get_queryset(self):
        # override get_queryset() to filter in only lists belonging to the current user,
        # eliminating the need to define a model in this class.
        return List.objects.filter(user=self.request.user).order_by('-last_modified')

    # override dispatch to decorate this view with login_required
    @method_decorator(login_required)
    def dispatch(self, *args, **kwargs):
        return super(MyListsView, self).dispatch(*args, **kwargs)


class ListItemsView(ListView):
    """Display a list's items"""
    template_name = 'cmv_app/list_items.html'
    context_object_name = 'list_items'

    def get_queryset(self):
        # get a particular list's items
        items = Item.objects.filter(list=self.kwargs['list_id']).order_by('-created_date')
        return items

    def get_context_data(self, **kwargs):
        # Call the base implementation first to get a context
        context = super(ListItemsView, self).get_context_data(**kwargs)
        # Add the list, needed for the template to lookup urls for the item detail page
        context['list'] = self.list
        return context

    @method_decorator(login_required)
    def dispatch(self, request, *args, **kwargs):
        self.list = get_object_or_404(List, pk=kwargs['list_id'])
        # this is a security check: a user can only access his own lists 
        # (else raise PermissionDenied)
        request = list_valid_for_user(request, self.list) 
        return super(ListItemsView, self).dispatch(request, *args, **kwargs)


class ItemDetailView(DetailView):
    """Show detail for one item"""
    template_name = 'cmv_app/item_detail.html'

    def get_object(self):
        return self.item

    @method_decorator(login_required)
    def dispatch(self, request, *args, **kwargs):
        # fetching list and item in here instead of in get_object() in order to implement
        # security checks
        self.list = get_object_or_404(List, pk=kwargs['list_id'])
        self.item = get_object_or_404(Item, pk=kwargs['item_id'])
        # user can only access his lists (else raise PermissionDenied)
        request = list_valid_for_user(request, self.list) 
        # item must be associated with the specified list (else raise PermissionDenied)
        request = item_valid_for_list(request, self.item, self.list)
        return super(ItemDetailView, self).dispatch(request, *args, **kwargs)

    def get_context_data(self, **kwargs):
        # Call the base implementation first to get a context
        context = super(ItemDetailView, self).get_context_data(**kwargs)
        # Add in the elements needed for the template to construct url for link to list
        context['list'] = self.list
        return context

【问题讨论】:

  • 我特别关心在dispatch()中添加业务逻辑。它有效,但我怀疑有更好/更“标准”的方式?
  • 这个问题似乎是题外话,因为它是关于审查代码的,应该在codereview.stackexchange.com
  • 糟糕,谢谢马克西姆。我不知道 codereview.stackexchange.com。我去那里试试。

标签: python django django-class-based-views django-generic-views


【解决方案1】:

例如,对于ListItemsViews,在您的调度中只做:

self.list = kwargs['list']
self.list_id = kwargs['list_id']

然后,这转到get_context_data

self.list = get_object_or_404(List, pk=self.list_id)

然后发给get_queryset

items = Item.objects.filter(list=self.list_id).order_by('-created_date')

【讨论】:

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