【发布时间】:2018-11-06 20:24:51
【问题描述】:
我来自这个问题https://github.com/carltongibson/django-filter/issues/919,这是发生了什么:
我想通过 django-filter 对列表进行一些模糊搜索(某些列表搜索和单个模糊搜索都可以)。
一、产品型号:
from django.db import models
class Product(models.Model):
...
name = models.CharField(max_length=16)
type = models.CharField(max_length=16)
...
以及存储在数据库中的两个产品:
{
"name": "tomato",
"type": "vegetable"
}
{
"name": "orange",
"type": "fruit"
}
和序列化器:
from rest_framework import serializers
from .models import Product
class ProductSerializer(serializers.ModelSerializer):
name = serializers.CharField()
type = serializers.CharFIeld()
class Meta:
model = Product
fields = '__all__'
然后ListFilter:
import django_filters
from django_filters.fields import Lookup
from .models import Product
class ListFilter(django_filters.Filter):
def filter(self, qs, value):
value_list = value.split(u',')
return super(ListFilter, self).filter(qs, Lookup(value_list, 'in'))
然后查看(我将ListFilter 放在utils.django_filters):
from rest_framework import generics
from django_filters import rest_framework as filters
from utils.django_filters import ListFilter
from .models import Product
from .serializers import ProductSerializer
class ProductFilter(filters.FilterSet):
type = ListFilter(name='type')
class Meta:
model = Product
fields = {
'type': ['exact', 'contains'],
}
class ProductList(generics.ListCreateAPIView):
queryset = Product.objects.all()
serializer_class = ProductSerializer
filter_backends = (filters.DjangoFilterBackend,)
filter_class = ProductFilter
最后的网址:
from django.urls import path
from . import views
path('product-list', views.ProductList.as_view(), name='product-list')
以下是测试用例和结果:
GET /api/product/product-list?type=fruit -> [orange]
GET /api/product/product-list?type=vegetable -> [tomato]
GET /api/product/product-list?type=fruit,vegetable -> [orange, tomato]
GET /api/product/product-list?type__contains=fru -> [orange]
GET /api/product/product-list?type__contains=vege -> [tomato]
GET /api/product/product-list?type__contains=fru,vege -> []
GET /api/product/product-list?type__contains=fruit,vegetable -> []
我希望最后两个结果是[orange, tomato],可以这样做吗?
【问题讨论】:
标签: django django-rest-framework django-filter