Python 中最快的代理迭代

Question

假设我有一个包含 10,000 多个代理的列表

proxy_list = ['ip:port','ip:port',.....10,000+ items]

如何迭代它以获得适用于我的电脑的代理？使用以下代码可以找到它，但需要 5*10,000 秒才能完成。如何更快地遍历列表？

import requests
result=[]
for I in proxy_list:
    try:
        requests.get('http:\\www.httpbin.org\ip',proxies = {'https' : I, 'http' : I } ,timeout = 5)
        result.append(I)
    except:
        pass

Answer 1

您可以使用线程，这将允许程序一次检查多个代理。

import requests
import threading
import concurrent.futures

appendLock = threading.Lock() """This is to keep multiple threads from appending 
to the list at the same time"""

workers = 10 """This is the number of threads that will iterate through your proxy list.
In my experience, increasing this number higher than 30 causes problems."""

proxy_list = ['ip:port','ip:port',.....10,000+ items]

result = []

def proxyCheck(proxy):
    try:
        requests.get('http://www.httpbin.org/ip',proxies = {'https' : I, 'http' : I } ,timeout = 5)
        with appendLock:
            result.append(I)
    except:
        pass

with concurrent.futures.ThreadPoolExecutor(max_workers=workers) as executor:
    for proxy in proxy_list:
        executor.submit(proxyCheck(proxy))