无法使用php将uiimage从ios上传到服务器

Question

这是我的代码：

NSString *image_name = @"test.jpg";
NSData *imageData = UIImageJPEGRepresentation(self.myImage.image, 0.1);

NSString *urlString = [NSString stringWithFormat:@"http://xxx/uploadfile.php"];
NSMutableURLRequest *request =[[NSMutableURLRequest alloc] init];
[request setURL:[NSURL URLWithString:urlString]];
[request setHTTPMethod:@"POST"];

NSString *boundary = @"14737809831466499882746641449";
NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@",boundary];
[request addValue:contentType forHTTPHeaderField: @"Content-Type"];

NSMutableData *body = [NSMutableData data];

[body appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]];

[body appendData:[[NSString stringWithFormat:@"Content-Disposition:form-data; name=\"file\"; filename=\"%@\"\r\n",image_name] dataUsingEncoding:NSUTF8StringEncoding]];
[body appendData:[@"Content-Type: application/octet-stream\r\n\r\n" dataUsingEncoding:NSUTF8StringEncoding]];
[body appendData:[NSData dataWithData:imageData]];
[body appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]];

[request setHTTPBody:body];

NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
NSString *returnString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding];
NSLog(@"%@", returnString);

这里是php代码：

<?php 
$uploaddir = 'C:\'; 
$file = basename($_FILES['file']['name']); 
$uploadfile = $uploaddir . $file; 
if (move_uploaded_file($_FILES['file']['tmp_name'], $uploadfile)) 
    { echo "Received file" . $_FILES; } 
?> 

但它不起作用。响应字符串说：

500 - Internal server error.
There is a problem with the resource you are looking for, and it cannot be displayed.

Answer 1

这是IOS端的代码

- (IBAction)uploadImage {
    /*
     turning the image into a NSData object
     getting the image back out of the UIImageView
     setting the quality to 90
    */
    NSData *imageData = UIImageJPEGRepresentation(image.image, 90);
    // setting up the URL to post to
    NSString *urlString = @"http://XXXXX.com/test-upload.php";

    // setting up the request object now
    NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease];
    [request setURL:[NSURL URLWithString:urlString]];
    [request setHTTPMethod:@"POST"];

    /*
     add some header info now
     we always need a boundary when we post a file
     also we need to set the content type

     You might want to generate a random boundary.. this is just the same
     as my output from wireshark on a valid html post
    */
    NSString *boundary = [NSString stringWithString:@"---------------------------14737809831466499882746641449"];
    NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@",boundary];
    [request addValue:contentType forHTTPHeaderField: @"Content-Type"];

    /*
     now lets create the body of the post
    */
    NSMutableData *body = [NSMutableData data];
    [body appendData:[[NSString stringWithFormat:@"--%@",boundary] dataUsingEncoding:NSUTF8StringEncoding]];
    [body appendData:[[NSString stringWithString:@"Content-Disposition: form-data; name=\"userfile\"; filename=\"ipodfile.jpg\""] dataUsingEncoding:NSUTF8StringEncoding]];
    [body appendData:[[NSString stringWithString:@"Content-Type:application/octet-stream"] dataUsingEncoding:NSUTF8StringEncoding]];
    [body appendData:[NSData dataWithData:imageData]];
    [body appendData:[[NSString stringWithFormat:@"--%@--",boundary] dataUsingEncoding:NSUTF8StringEncoding]];
    // setting the body of the post to the reqeust
    [request setHTTPBody:body];

    // now lets make the connection to the web
    NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
    NSString *returnString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding];

    NSLog(returnString);
}

这里是抓取上传文件的php函数：

$uploaddir = './uploads/';
$file = basename($_FILES['userfile']['name']);
$uploadfile = $uploaddir . $file;

if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) {
        echo "http://XXXXXXX.com/uploads/{$file}";
}

之后，您需要使用 xampp 或 WAMMP 转到您的 PHP 项目放置的目录，以提供完全访问权限，再考虑需要在该项目调用中创建一个文件夹，作为本教程的 uploads。