尝试使用 slug 时找不到对象，错误 404

Question

我不久前使用 slugs 做了一个小项目，当时一切正常。现在，当我尝试打开一个 slug 时，我得到一个“找不到对象”页面和一个 404 错误。

这是我的 .htaccess 文件：

RewriteEngine on
Options +FollowSymlinks
RewriteBase /
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule ^(.*)/$ /benc/$1 [L,R]
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule ^.*$ /benc/index.php [L,QSA];

通过这个功能，我在主页上显示了一些博客（带有链接到单个博客或 slug 的标签）：

   function showBlogs($limit) {
        global $conn;

        $result = mysqli_query($conn, "SELECT a.*, b.* FROM blogs a, slugs b WHERE b.blogID = a.idBlog");

        while ($row = mysqli_fetch_array($result)) {
                echo '<div class="container_blogs" id="' . $row['idBlog'] . '">';
                echo '<h1 class="title_blog">' . $row['title'] . '</h1>';
                echo '<h3 class="desc_blog">' . $row['blogDesc'] . '</h3>';
                echo '<p class="text_blog">' . $row['content'] . '</p>';
                echo '<div class="link_container"><a href="http://localhost:8080/benc/' . $row['slug'] . '">' . "Read more" . '</a></div>';
                echo '</div>'; 
        }
    }

这是在单独页面上显示单个博客的代码：

global $conn;
define("SYSTEMNAME","TENPCMS1.0");
//include files after defining slug, there's a check to prevent direct execution of php files.
// include_once('template.php');
include_once('database.php');
// include_once('fetch_mysql.php');
$root = '/benc/';
//de root moet straks worden opgehaald uit mysql
$url = $_SERVER['REQUEST_URI'];
$slug = str_replace($root,"",$url);
define("SLUG", $slug);
define("DOMAIN", $_SERVER['HTTP_HOST']);
if(SLUG == NULL ){

    function showBlog() {
        ?>

    <h1>Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Aenean commodo ligula eget dolor.
                        Aenean massa. Cum sociis natoque penatibus et magnis dis parturient montes,
                        nascetur ridiculus mus. Donec quam felis, ultricies nec, pellentesque eu, pretium quis, sem.</h1>
    <a href="#"><i class="fas fa-angle-right"></i> Nieuwe Website</a>




    <?php
    }


}
else {
    function showBlog() {
            global $conn;
            global $slug;

            $slugs = "SELECT a.* FROM blogs a, slugs b WHERE a.idBlog=b.blogId AND b.slug='$slug'";
            // $slug = "SELECT * FROM blogs WHERE idBlog = $slugs";
            $result = $conn->query($slugs);
            while ($row = mysqli_fetch_array($result)) {
                echo '<div class="container_blogs">';
                echo '<div class="blog_container_p" id="' . $row['idBlog'] . '">';
                echo '<h1 class="blog_title_p">' . $row['title'] . '</h1>';
                echo '<h3 class="blog_desc_p">' . $row['blogDesc'] . '</h3>';
                echo '<p class="blog_text_p">' . $row['content'] . '</p>';
                echo '</div>';
                echo '</div>';
            }
        }


}
include_once('template.php');

谁能告诉我为什么我收到“找不到对象”错误？

Answer 1

没关系。我觉得自己像个白痴。感谢我的 macbook，我的 .htaccess 文件已更改为 _htaccess ... 直到一分钟前才注意到。