【发布时间】:2015-02-23 01:27:57
【问题描述】:
我有一个 ajax 上传脚本,我将在下面发布。它将上传任何具有任何扩展名的文件。我希望它只上传 .png 文件,但我不知道该怎么做。
这是我的文件:
<h1>Ajax File Upload Demo</h1>
<form id="myForm" action="upload.php" method="post" enctype="multipart/form-data">
Name it:
<input type="text" name="upload_name">
<br>
<input type="file" size="60" name="myfile">
<input type="submit" value="Ajax File Upload">
</form>
<div id="progress">
<div id="bar"></div>
<div id="percent">0%</div >
</div>
<br/>
<div id="message"></div>
<script>
$(document).ready(function()
{
var options = {
beforeSend: function()
{
$("#progress").show();
//clear everything
$("#bar").width('0%');
$("#message").html("");
$("#percent").html("0%");
},
uploadProgress: function(event, position, total, percentComplete)
{
$("#bar").width(percentComplete+'%');
$("#percent").html(percentComplete+'%');
},
success: function()
{
$("#bar").width('100%');
$("#percent").html('100%');
},
complete: function(response)
{
$("#message").html("<font color='green'>"+response.responseText+"</font>");
},
error: function()
{
$("#message").html("<font color='red'> ERROR: unable to upload files</font>");
}
};
$("#myForm").ajaxForm(options);
});
</script>
PHP:
<?php
$upload_name = $_POST['upload_name'];
$idx = strpos($_FILES['myfile']['name'],'.');
$ext = substr($_FILES['myfile']['name'],$idx);
$file_name = $upload_name . $ext;
$output_dir = "uploads/";
if(isset($_FILES["myfile"]))
{
//Filter the file types , if you want.
if ($_FILES["myfile"]["error"] > 0)
{
echo "Error: " . $_FILES["file"]["error"] . "<br>";
}
else
{
//move the uploaded file to uploads folder;
// move_uploaded_file($_FILES["myfile"]["tmp_name"],$output_dir. $_FILES["myfile"]["name"]);
// echo "Uploaded File :".$_FILES["myfile"]["name"];
move_uploaded_file($_FILES["myfile"]["tmp_name"],$output_dir.$file_name);
echo "Uploaded File :" . $file_name;
}
}
?>
抱歉,我是新手,代码块对我不起作用。如果有人可以更新,那就太好了。
【问题讨论】:
-
你必须用
$_FILES["myfile"]["type"]检查你上传文件的mime类型,看看它是否等于image/png。