MySQL Inner join 过去 7 天销量最高答案

【问题标题】：MySQL Inner join last 7 days find top salesMySQL Inner join 过去 7 天销量最高
【发布时间】：2018-08-17 09:39:44
【问题描述】：

sqlfiddle.com/#!9/ecede/1

表格和样本数据：

CREATE TABLE orders(
    order_id INT NOT NULL,
    created_at DATE NOT NULL,
    country CHAR(10),
    total_net_revenue INT NOT NULL,
    total_gross_revenue INT NOT NULL,
    total_quantity INT NOT NULL
);

INSERT INTO orders VALUES
    (101,'2018-03-08',"China",150,250,20),
    (102,'2018-03-08',"China",140,280,67),
    (103,'2018-03-08',"China",150,190,15),
    (111,'2018-02-09',"China",150,190,15),
    (104,'2018-03-07',"China",150,190,15);

CREATE TABLE products_inventory(
    product_id INT NOT NULL,
    product_name CHAR(10),
    brand_name CHAR(10),
    purchase_price INT NOT NULL,
    selling_price INT NOT NULL,
    units_remaining_in_inventory INT NOT NULL
);

INSERT INTO products_inventory VALUES
    (97,"3ds","Nintendo",100,250,40),
    (98,"Switch","Nintendo",140,280,102),
    (99,"Mini","Nintendo",40,190,30),
    (131,"Fail","Nintendo",40,190,1310);

CREATE TABLE items_in_order(
    order_id INT NOT NULL,
    country CHAR(10),
    brand CHAR(10),
    product_name CHAR(10),
    product_ID INT NOT NULL,
    net_revenue INT NOT NULL,
    gross_revenue INT NOT NULL,
    quantity INT NOT NULL
);

INSERT INTO items_in_order VALUES
    (101,"China","Nintendo","3ds",97,150,250,20),
    (102,"China","Nintendo","Switch",98,140,280,67),
    (103,"China","Nintendo","Mini",99,150,190,15),
    (111,"China","Nintendo","Fail",131,150,190,15),
    (104,"China","Nintendo","3ds",97,150,250,20);

查询：

SELECT i1.product_name, i1.product_id, i1.brand,
SUM(i1.net_revenue) AS net_revenue_last7days,
(p2.selling_price - p2.purchase_price) AS item_margin,
remaining_stock

FROM items_in_order i1

INNER JOIN(
  SELECT o1.order_id,o1.country,SUM(o1.total_net_revenue) AS net_revenue,
  SUM(o1.total_gross_revenue) AS gross_revenue
  FROM orders o1
  WHERE (created_at >= NOW() - INTERVAL 7 DAY) AND o1.country = "China"
  GROUP BY 1,2
  ) o2
  ON o2.order_id = i1.order_id AND o2.country = i1.country AND o2.net_revenue = i1.net_revenue
  AND o2.gross_revenue = i1.gross_revenue

INNER JOIN(
  SELECT product_id, product_name, brand_name AS brand, purchase_price, selling_price,
  SUM(units_remaining_in_inventory) AS remaining_stock
  FROM products_inventory p1
  GROUP BY 1,2,3
  ) p2
  ON i1.product_id = p2.product_id AND i1.product_name = p2.product_name AND i1.brand = p2.brand

WHERE i1.country = "China" AND i1.brand = "Nintendo"
GROUP BY 1,2,3
ORDER BY 4 DESC
LIMIT 10

我正在尝试获取每个品牌每个产品过去 7 天的总收入，并加入表格：orders & items_in_order。

我的 INNER JOIN 有问题吗？它应该显示 3ds 的最后 7 天的净收入 300。

我想要实现的其他信息：

过去 7 天任天堂在中国的单品最高收入
显示每个项目的当前库存单位
显示每个项目的边距

【问题讨论】：

删除AND o2.gross_revenue = i1.gross_revenue会得到想要的结果
谢谢，我发现它实际上是在创建表中的错误，订单表中第二个 3ds 的总收入值错误：250 而不是 190，这解释了加入数据失败
那是我的另一个理论。
您的表中似乎有很多冗余数据。为什么country 在orders 和items_in_order 中都有？商品可以与订单本身位于不同的国家/地区吗？

标签： mysql sql

【解决方案1】：

第一个JOIN 的这一部分阻止了订单#104：

AND o2.gross_revenue = i1.gross_revenue

orders 表中订单 #104 的总收入为 190，但在 items_in_order 表中为 250。

如果你从JOIN 中删除它，你会得到net_revenue_last7days = 300。

http://sqlfiddle.com/#!9/ecede/10

【讨论】：