【发布时间】:2020-01-18 23:29:42
【问题描述】:
我开发了一个搜索栏,可以从我的产品列表中搜索超过 10,000 种产品的项目。当用户键入一个单词时,用户可以看到基于用户输入的 8 个项目的建议列表。这是我的代码,代码运行良好。但我想做的是增加建议列表。我不知道该怎么做。所以如果有人可以请帮助我。
Nsearch.blade.php
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/css/bootstrap.min.css" integrity="sha384-ggOyR0iXCbMQv3Xipma34MD+dH/1fQ784/j6cY/iJTQUOhcWr7x9JvoRxT2MZw1T" crossorigin="anonymous">
<script
src="https://code.jquery.com/jquery-3.4.1.js"
integrity="sha256-WpOohJOqMqqyKL9FccASB9O0KwACQJpFTUBLTYOVvVU="
crossorigin="anonymous"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-3-typeahead/4.0.2/bootstrap3-typeahead.js"></script>
</head>
<body>
<div class="container">
<h1> test products </h1>
<input type="text" class="typeahead form-control" name="name">
</div>
<script type="text/javascript">
var path = "{{route('nautocomplete')}}";
$('input.typeahead').typeahead({
source:function(query,process){
return $.get(path,{query:name},function (data) {
return process(data);
})
}
});
</script>
</body>
</html>
NSearchController.php
<?php
namespace App\Http\Controllers\Shop;
use App\Product;
use Illuminate\Http\Request;
use App\Http\Controllers\Controller;
class NSearchController extends Controller
{
public function index(){
return view('shop.Nsearch');
}
public function autocomplete(Request $request){
$data = Product::select("name")
->where("name","LIKE","%{$request->input('name')}%")->get();
return response ()->json($data);
}
}
web.php(路由)
Route::get ('/nsearch','Shop\NSearchController@index')->name('nsearch');
Route::get ('/nautocomplete', 'Shop\NSearchController@autocomplete')->name('nautocomplete');
当前视图
【问题讨论】:
标签: jquery laravel search autocomplete bootstrap-typeahead