【发布时间】:2025-11-27 18:45:01
【问题描述】:
import schedule
import time
def job1():
print ("Four weeks count")
def job2():
print ("Six weeks")
def job3():
print ("Eleven weeks")
def job4():
print ("Twelve weeks")
schedule.every(1).seconds.do(job1)
schedule.every(2).seconds.do(job2)
schedule.every(3).seconds.do(job3)
schedule.every(4).seconds.do(job4)
while True:
schedule.run_pending()
time.sleep(1)
#
如何编写可以在几周而不是几秒内安排工作的代码。我也想知道哪天哪天会发生哪四个星期。见下文。
从日期时间导入时间增量 print ("四个星期生根:" + str(datetime.now() + timedelta(weeks=4))) print ("将植物移至硬化区域:" + str(datetime.now() + timedelta(weeks=6))) print ("G camp:" + str(datetime.now() + timedelta(weeks=11))) print ("PQI:" + str(datetime.now() + timedelta(weeks=12))) 四个星期生根:2020-04-28 14:05:02.033788 将植物移至硬化区:2020-05-12 14:05:02.033788 G营:2020-06-16 14:05:02.033788 PQI:2020-06-23 14:05:02.033788
【问题讨论】:
标签: python