Django manytomany 通过创建表单和视图

Question

我是 Django 的新手，我正在建立一个工作委员会。 但我不明白如何创建一个表单来获取 M2M 的相关字段。

这是我的代码：

#views.py
class JobDetails(generic.DetailView):

    model = Job
    template_name = 'companies/job-detail.html'

    def get_context_data(self, **kwargs):
        context = super(JobDetails, self).get_context_data(**kwargs)
        context['company_detail'] = Company.objects.all()
        return context

    def apply(request):
        if request.method == "POST":
            form = ApplyForm(request.POST)
            if form.is_valid():
                 form.save(commit=False)

                #create job
                job = Job.objects.all.get(pk=pk)

                #create candidate
                candidate = User.objects.all.get(pk=pk)

                #assign to the through table
                candidatetojob = CandidateToJob.objects.create(job=job, candidate=candidate)


                form.save()
                candidatetojob.save()   



                 return HttpResponseRedirect('/jobs/')
         else:
                form = ApplyForm()

         return render_to_response(
             "companies/form-candtojob.html",
             {'form': form}
         )


 #forms.py
 class ApplyForm(ModelForm):

    class Meta:
        model = CandidateToJob
        exclude = ['candidate', 'job', 'status']


 #models.py
 class Job(models.Model):
    company = models.ForeignKey(Company)
    candidate = models.ManyToManyField('Candidate', through='CandidateToJob')
    title = models.CharField(max_length=500)
    pub_date = models.DateField(auto_now_add=True)
    ...

    def __unicode__(self):
        return self.title

    def get_absolute_url(self):
        return reverse('jobdetail', kwargs={'pk': self.pk})

 class Candidate(models.Model):
    user = models.OneToOneField(User, primary_key=True)
    photo = models.ImageField(upload_to='candidateprofile/%Y/%m/%d')
    ...

    def __unicode__(self):
       return self.user.username


 class CandidateToJob(models.Model):
    job = models.ForeignKey(Job, related_name='applied_to')
    candidate = models.ForeignKey(Candidate, related_name='from_user')
    STATUS_CHOICES = (
        ('0', 'New'),
        ('1', 'Not approved'),
        ('2', 'Approved'),
        ('3', 'Hired')
     )
    status = models.CharField(max_length=2, choices=STATUS_CHOICES)

    def __unicode__(self):
        return self.job.candidate.user.username

但在我的 template.html 中，正在登录的用户候选人申请工作（通过提交表单按钮）我收到 405 错误。我只能在管理员中执行此操作。

关于我做错了什么的一些想法？ 提前致谢。

Answer 1

您收到 405 错误，因为您没有定义任何 POST 方法。要接受 POST 请求，您需要一个 post 方法。你有一个 apply 方法，你认为它会被 POST，但它永远不会被调用。将您的应用方法更改为：

def post(self, request, *args. **kwargs):
    form = ApplyForm(request.POST)

    if form.is_valid():
        form.save(commit=False)

        #create job
        job = Job.objects.all.get(pk=pk)

        #create candidate
        candidate = User.objects.all.get(pk=pk)

        #assign to the through table
        candidatetojob = CandidateToJob.objects.create(job=job, candidate=candidate)

        form.save()
        candidatetojob.save()   

        return HttpResponseRedirect('/jobs/')

     return render_to_response(
         "companies/form-candtojob.html",
         {'form': form}
     )

Answer 2

我让它工作了。我就是这样做的。谢谢。

def post(self, request, *args, **kwargs):
    form = self.form_class(request.POST)

    if form.is_valid():
        form.save(commit=False)

        #get the job
        job = self.get_object(queryset=Job.objects.all())

        #get the user candidate
        candidate = Candidate.objects.get(pk=request.user)

        #assign to the through table
        candidatetojob = CandidateToJob.objects.create(job=job, candidate=candidate)

        candidatetojob.save()


        return HttpResponseRedirect('/jobs/')

    return render(request, self.template_name, {'form': form})